- #1
shamieh
- 539
- 0
I do not understand how I would do this with long division since there is only 2 terms. I can't remember the trick. Here is what I have so far.
\(\displaystyle
\int \frac{3x^2 - 2}{x^2 - 2x - 8} dx\)
so I got \(\displaystyle \int 3 + \frac{x^2 - 2}{(x - 4)(x + 2)}\)
I'm not sure if that's right? I just factored it out instead of long division. I Don't recall what "synthetic division" is either.
So I have \(\displaystyle (x - 4)(x + 2) = A(x+2) + B(x-4)\)Am I on the right track or no?
\(\displaystyle
\int \frac{3x^2 - 2}{x^2 - 2x - 8} dx\)
so I got \(\displaystyle \int 3 + \frac{x^2 - 2}{(x - 4)(x + 2)}\)
I'm not sure if that's right? I just factored it out instead of long division. I Don't recall what "synthetic division" is either.
So I have \(\displaystyle (x - 4)(x + 2) = A(x+2) + B(x-4)\)Am I on the right track or no?