- #1
Chandasouk
- 165
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Point charge 2.0 uC is located at X= 0, X= 0.30m , point charge -2.0uC is located at X= 0 Y= -0.30m . What are (a)the magnitude and (b)direction of the total electric force that these charges exert on a third point charge Q= 5.0 uC at X= 0.40 , Y= 0?
I drew a diagram of what was going on and used Pythagorean theorem to find out that the distance between Q1 and Q is .50m as well as Q2 and Q. I then broke Q into its components and solved for (F1 on Q)x and (F1 on Q)y. But first
(F1 on Q) = (8.988*10^9)[(2*10^-60 * (5*10^-6)/(.50m)2] = 0.35952N
(F1 on Q)x= 0.35952N*cos[tex]\theta[/tex] = 0.35952N(.40/.50) = 0.287616N
(F1 on Q)Y= -0.35952N*sin[tex]\theta[/tex] = -0.35952N(.30/.50) = -0.215712N
Where do I go from here? And how do I find theta?
I drew a diagram of what was going on and used Pythagorean theorem to find out that the distance between Q1 and Q is .50m as well as Q2 and Q. I then broke Q into its components and solved for (F1 on Q)x and (F1 on Q)y. But first
(F1 on Q) = (8.988*10^9)[(2*10^-60 * (5*10^-6)/(.50m)2] = 0.35952N
(F1 on Q)x= 0.35952N*cos[tex]\theta[/tex] = 0.35952N(.40/.50) = 0.287616N
(F1 on Q)Y= -0.35952N*sin[tex]\theta[/tex] = -0.35952N(.30/.50) = -0.215712N
Where do I go from here? And how do I find theta?