Photoelectric effect and Aluminum

In summary, a 0.4 kilogram sample of Aluminum at 115 degrees Celsius is put into a container containing 0.5 kilograms of water at 15 degrees Celsius. The specific heat of Aluminum is 900 kJ/kg*C and the specific heat of water is 4186 kJ/kg*C. The heat absorbed by the water is smaller compared to the heat liberated by the aluminum. This is because heat is a form of energy measured in Joules, and the specific heat of water is higher than that of aluminum. This concept is similar to pouring a cup of water into a bucket, where the mass gained by the bucket is the same as the mass lost by the cup. Furthermore, the question about the photoelectric effect
  • #1
n108
13
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A 0.4 kilogram sample of Aluminum at 115 degrees Celsius is put into a container containing 0.5 kilograms of water at 15 degrees Celsius. Neglecting the small amount of energy absorbed by the container and knowing that the specific heat of Aluminum is 900 kJ/kg*C, and the specific heat of the water is 4186 kJ/kg*C answer the following question.

Compared to the heat liberated by the aluminum, the heat absorbed by the water is

greater. wrong

smaller.

the same.

is it smaller or the same?
why?
 
Last edited:
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  • #2
what are the units of heat? what then is heat?
 
  • #3
heat is...energy, thermal energy, or a change in temperature, measured in Joules
 
  • #4
and what things have you learned about energy?
 
  • #5
It is exactly the same with the following example. You pour a cup of water into a bucket. Then asked: compare the mass gained by the bucket and the mass lost by the cup. The answer now so simple.
 
  • #6
It's the same since they already told you to ignore the heat absorbed by the container.
 
  • #7
Hmmm... why is this a question about the photoelectric effect? It seems to be just a thermodynamics question, perhaps there's a trick somewhere?
 

Related to Photoelectric effect and Aluminum

1. What is the photoelectric effect?

The photoelectric effect is the phenomenon in which electrons are emitted from a material when it is exposed to light of a certain frequency or above.

2. How does aluminum exhibit the photoelectric effect?

Aluminum is a metal that has a low work function, meaning it requires a low amount of energy to release electrons. When light of a high enough frequency strikes the surface of aluminum, it can cause electrons to be released, demonstrating the photoelectric effect.

3. What is the threshold frequency for aluminum in the photoelectric effect?

The threshold frequency for aluminum is approximately 7.28 x 10^14 Hz. This means that light with a frequency below this value will not cause the photoelectric effect in aluminum.

4. How does the intensity of light affect the photoelectric effect in aluminum?

The intensity of light, or the number of photons per unit area, does not affect the photoelectric effect in aluminum. The only factor that affects the number of electrons released is the frequency of the light.

5. What is the significance of the photoelectric effect in relation to quantum mechanics?

The photoelectric effect was one of the first experiments that provided evidence for the particle-like nature of light, known as photons. It also helped to explain the concept of energy quantization, which is a fundamental principle of quantum mechanics.

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