- #1
parshyaa
- 307
- 19
- Acording to this diagram vector P = vector BC and vector Q = vector OB(their magnitudes are also respectively equal.)
- Therefore acoording to the congruency of triangles angle alpha = (theta)/2. But this is not right( what's wrong )
- {Tan(alpha) = Qsin(theta)/(P + Qcos(thets)) ]
- Why resultant vector of P vector and Q vector touches C to form OC vectors.
- Does the length of vector represents its magnitude.