Normalizing Wave Functions Over Multiple Regions

In summary, to normalize the given wave function, we need to integrate the piecewise-function squared over the entire interval and set it equal to 1. This can be done by splitting the interval into three regions, (-∞, -a/2), (-a/2, a/2), and (a/2, +∞), and integrating each region separately. This will give us the value of the coefficient A, which can then be used to determine the values of the other coefficients C and D.
  • #1
SHISHKABOB
541
1

Homework Statement



I need to normalize the following wave function in order to determine the value of the coefficients. This is from the basic finite square well potential.

[itex]\Psi(x) = Ae^{k_{1}x},for \ x < -a/2[/itex]
[itex]\Psi(x) = Csin(k_{2}x),for \ -a/2 \leq x \leq a/2[/itex]
[itex]\Psi(x) = De^{-k_{1}x}, for \ x > a/2[/itex]

Homework Equations



[itex]\int\left|\Psi(x)\right|^{2} dx = 1[/itex]

The Attempt at a Solution



Do I do an integral for each region, with the limits of integration being the boundaries of each region, and that integral normalized to 1 for each of those regions? Or do I add up those integrals with the same limits of integration and then set that equal to 1?
 
Last edited:
Physics news on Phys.org
  • #2
You use the fact that the wavefunction is continuous at each connecting point,
(-a/2), a/2, to write C and D in terms of A.

Then you integrate the piecewise-function squared over the whole interval to tell
you what A should be.

[also this might be a solution to the finite square well but it's not the most general solution, which
allows cos(kx) in the middle as well. <-- totally meant this to be punny
]
 
  • #3
SHISHKABOB said:
Or do I add up those integrals with the same limits of integration and then set that equal to 1?

This. More explicitly:

$$\int_{-\infty}^{+\infty} {|\Psi|^2 dx} = 1 \\
\int_{-\infty}^{-a/2} {|\Psi_1|^2 dx}
+ \int_{-a/2}^{+a/2} {|\Psi_2|^2 dx}
+ \int_{+a/2}^{+\infty} {|\Psi_3|^2 dx} = 1$$

This is the same thing as if you were to integrate a single function over the entire range from -∞ to +∞, by splitting up that range into three pieces and doing those as separate integrals for whatever reason.
 

Related to Normalizing Wave Functions Over Multiple Regions

1. What is the purpose of normalizing wave functions over multiple regions?

The purpose of normalizing wave functions over multiple regions is to ensure that the total probability of finding a particle in any of the regions is equal to 1. This allows for consistent and meaningful calculations and interpretations of quantum systems.

2. How is normalization of wave functions over multiple regions achieved?

Normalization of wave functions over multiple regions is achieved by finding the normalization constant, which is the square root of the integral of the square of the wave function over all regions. The wave function is then divided by this constant to ensure that the total probability is equal to 1.

3. What happens if a wave function is not normalized over multiple regions?

If a wave function is not normalized over multiple regions, the total probability of finding a particle in any of the regions will not equal 1. This can lead to incorrect calculations and interpretations of quantum systems.

4. Can wave functions be normalized over an infinite number of regions?

Yes, wave functions can be normalized over an infinite number of regions. This is often necessary in quantum systems with continuous variables, such as position or energy.

5. Are there any limitations to normalizing wave functions over multiple regions?

One limitation to normalizing wave functions over multiple regions is that it can only be done if the wave function is square-integrable, meaning it has a finite integral over all regions. Additionally, normalization does not guarantee that the wave function will accurately describe the quantum system, as it only ensures the total probability is equal to 1.

Similar threads

  • Advanced Physics Homework Help
Replies
30
Views
2K
  • Advanced Physics Homework Help
Replies
10
Views
668
  • Advanced Physics Homework Help
Replies
19
Views
699
  • Advanced Physics Homework Help
Replies
5
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
144
  • Advanced Physics Homework Help
Replies
9
Views
1K
  • Advanced Physics Homework Help
Replies
8
Views
564
  • Advanced Physics Homework Help
Replies
5
Views
1K
  • Advanced Physics Homework Help
Replies
3
Views
1K
  • Advanced Physics Homework Help
Replies
3
Views
1K
Back
Top