Newton's Second Law: Calculating Net Force on a Wagon with a Child (28.5kg)

In summary, the wagon carrying a child with a mass of 28.5kg experiences a force of friction of 12.0N while being pulled at an angle of 40 degrees from the horizontal. To calculate the net force, a right angled triangle can be constructed with a 40 degree angle representing the force vectors. The horizontal component of the unknown force, F, is enough to overcome the frictional force. By doing vector addition of the weight force, W, and F, the net force can be determined at an angle of 130 degrees from the horizontal.
  • #1
Mathcaptor
14
0
A wagon carries a child. Together mass is 28.5kg. You pull on the handle of the wagon at an angle of 40degrees from the horizontal. The wagon travels over a level horizontal sidewalk. A force of friction of 12.0N acts on the wagon.

a) What is the net force acting on the wagon?



Note: I'm really having trouble with calculating this (triangle wise). Please help ASAP.
 
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  • #2
There's a force W operating vertically downwards. It's the weight of the trolley.
There's a force F pulling on the trolley. All I know about that force is that the horizontal component is sufficient to overcome a 12N frictional force.
So build a right angled triangle with a 40° angle in it to represent the force vectors. The hypotenuse is length F (unknown for the moment). The force adjacent to the 40° angle is length 12. Now can you calculate F?

Then you need to do the vector addition of W and F to find the net force.
The angle between F and W will be 90° + 40°.
 
  • #3


I am happy to assist with your question. According to Newton's Second Law, the net force acting on an object is equal to its mass multiplied by its acceleration (F=ma). In this situation, we have a wagon with a mass of 28.5kg and a force of friction acting on it of 12.0N.

To calculate the net force, we need to first break down the force pulling on the wagon into its horizontal and vertical components. The horizontal component of the force pulling on the wagon is equal to Fcos(40) = 15.4N, and the vertical component is equal to Fsin(40) = 18.3N.

Now, we can calculate the net force by subtracting the force of friction from the horizontal component of the pulling force. This gives us a net force of 15.4N - 12.0N = 3.4N.

Therefore, the net force acting on the wagon is 3.4N. This means that the wagon will experience an acceleration in the direction of the net force, which in this case is in the direction of the pulling force at an angle of 40 degrees from the horizontal. I hope this helps with your calculations.
 

Related to Newton's Second Law: Calculating Net Force on a Wagon with a Child (28.5kg)

What is Newton's Second Law?

Newton's Second Law, also known as the Law of Acceleration, states that the force applied to an object is directly proportional to its mass and acceleration.

How do I calculate force using Newton's Second Law?

To calculate force using Newton's Second Law, you need to know the mass of the object and its acceleration. Then, simply multiply the mass by the acceleration to find the force.

What are the units of force when using Newton's Second Law?

The units of force when using Newton's Second Law are measured in Newtons (N). One Newton is equal to 1 kilogram-meter per second squared (kg·m/s²).

What is the relationship between force, mass, and acceleration according to Newton's Second Law?

The relationship between force, mass, and acceleration according to Newton's Second Law is that force is directly proportional to both mass and acceleration. This means that as the mass or acceleration increases, so does the force.

How does Newton's Second Law relate to everyday life?

Newton's Second Law can be seen in everyday life in activities such as pushing a shopping cart, riding a bike, or throwing a ball. The force applied determines the resulting acceleration of the object.

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