- #1
skarthikselvan
- 5
- 0
Hi All,
While going through quantum conductnace derivation, I got stuck by an integral.
I = ((e*(h/2pi))/(m*pi)) Integral from 0 to infinity
dt / ( exp (((((h/2pi)^2 * t)/(2*m)) - Ef) / kT)) + 1)
The answer is
I = (2e/h)*kT*ln(1 + exp(Ef/kT))
I am stuggling to find the answer. Any help will be appreciated.
Thanks
Karthikselvan
While going through quantum conductnace derivation, I got stuck by an integral.
I = ((e*(h/2pi))/(m*pi)) Integral from 0 to infinity
dt / ( exp (((((h/2pi)^2 * t)/(2*m)) - Ef) / kT)) + 1)
The answer is
I = (2e/h)*kT*ln(1 + exp(Ef/kT))
I am stuggling to find the answer. Any help will be appreciated.
Thanks
Karthikselvan