- #1
wasi-uz-zaman
- 89
- 1
hi, I have just encountered following Maxwell equation in cgs system ▽×H = (1/c)((∂D)/(∂t))+((4π)/c)j,
▽×E = -(1/c)((∂B)/(∂t)),
▽.D = 4πρ,
▽.B = 0,
now , c is the speed of light in vacuum ,
my question is that we have studied earlier equation without this factor 'c' and 4pi in third equation, so how we get above equation in cgs( centimeter, gram, second ) system.
▽×E = -(1/c)((∂B)/(∂t)),
▽.D = 4πρ,
▽.B = 0,
now , c is the speed of light in vacuum ,
my question is that we have studied earlier equation without this factor 'c' and 4pi in third equation, so how we get above equation in cgs( centimeter, gram, second ) system.