- #1
Andy86
- 47
- 2
Homework Statement
A mass of 0.5kg is suspended from a flywheel,
The mass is released from rest and falls a distance of 0.5m in 1.5s
Mass of wheel = 3kg
Outside radius of wheel = 300mm
Radius of gyration = 212mm
Homework Equations
a- Linear acceleration of wheel
b- Angular acceleration of wheel
c- Tension in rope
d- Frictional torque
The Attempt at a Solution
[/B]
a) A = 2 x S / t^2
= 2x 0.5 / 1.5^2
= 0.444m/s
b) Inertia = mass x radius of gyration^2
= 3kg x 0.212^2
= 0.134832 KG M 2
Force = mass x acceleration
= 0.5kg x 0.444
= 0.222N
Torque = Force x Distance
= 0.222N x 0.3
= 0.0666 N
ANGULAR ACCELERATION = TORQUE / INERTIA
= 0.0666N / 0.134832
= 0.4944 Rad / s
c) Tension in rope
tension = Mg - Ma
= (0.5kg x 9.81) - (0.5 x 0.444)
= 4.683N
d) Frictional torque
Torque in rope = force x dist
= 4.683 x 0.3m
= 1.4049NM
Frictional Torque = Torque - Accel. Torque
= 1.4049 - ?
= ??
Im not too sure how to find the acceleration torque! I solved these questions (or thought I did a while ago and now I am writing up my solutions to submit them some bits don't make sense, any advice or guidance would be greatly appreciated)
Thanks
A