Making an exponential function linear

[Mathijsgri]

Homework Statement

a= e^D/R*T*G make a linear equations
and calculate the value for D and G
R=8,3 and constant
D,G=constant
T= variable

Homework Equations

y=ax+b
y=number^ax*b

The Attempt at a Solution

ax= E/(R*T)
x= 1/T

a= E/R

y= (E/R)*x+G

I don't know how to move on and if this is even correct/

 

[mfb]

ax= E/(R*T)

Where does that come from, and how is it supposed to help?

y= (E/R)*x+G

Where does that come from?

Start a step earlier. You want to make a linear equation. Linear in which variable?

If you are asked to calculate D and G, you'll need more than just the value of R.

R=8.3? In English the decimal separator is ".", not ",".

 

[Mark44]

Homework Statement

a= e^D/R*T*G make a linear equations
and calculate the value for D and G
R=8,3 and constant
D,G=constant
T= variable

Is there more to this problem than you have here?
Is the idea to find the linearization of your equation?

Homework Equations

y=ax+b
y=number^ax*b

How are these equations relevant? The first is, obviously, the equation of a line, but how do x and y relate to the variables in your given equation?

The Attempt at a Solution

ax= E/(R*T)
x= 1/T

a= E/R

y= (E/R)*x+G

I don't know how to move on and if this is even correct/

As already noted by @mfb, your work raises more questions than it answers.

 

[vela]

Try taking the logarithm of both sides, i.e., ##\log a = \log [Ge^{(D/R)T}]##, and expand out the right side using the properties of logarithms.

On a related note, is the exponent supposed to mean ##\frac{D}{RT}## or ##\frac{D}{R} T##?