Magnification in a Convex Lens: + or -?

[Gear2d]

In a conversing lens, if the object is not within the focal point, then the magnification is "-". But in the case where the object is placed in the focal point, then the magnification is "+"?

 

[Doc Al]

In a conversing lens, if the object is not within the focal point, then the magnification is "-". But in the case where the object is placed in the focal point, then the magnification is "+"?

Yes (you mean a converging lens). A "negative" linear magnification just means that the image is erect (and virtual). Read this: http://hyperphysics.phy-astr.gsu.edu/hbase/geoopt/raydiag.html#c2"

 

[sir-pinski]

This statement is correct. In a convex lens, the magnification can be either positive or negative depending on the position of the object. When the object is placed outside the focal point, the image formed is virtual and inverted, resulting in a negative magnification. However, when the object is placed at the focal point, the image formed is at infinity and has the same size as the object, resulting in a positive magnification. This shows the importance of understanding the position of the object in relation to the focal point in determining the magnification in a convex lens.