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zorro
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Homework Statement
A beam of electrons accelerated by a p.d. of 100V flies into a homogeneous magnetic field applied perpendicular to the plane of the paper towards the observer. The width of the field OP=L1=2cm. In the absence of m.f. the electron beam produces a spot at a point F on fluorescent screen AK, which is at a distance L2=6cm from teh edge of the m.f. When the m.f. is switched on the spot moves onto A along the path OQA. Find the displacement FA of the spot if the induction of the magnetic field B = 1.5 x 10-3 T
The Attempt at a Solution
Without explaining the concept- I am writing what I did in short.
Velocity gained by the electron, v= √(2eV/m)
v = 5.93 x 106m/s
r = 0.0225m
Now for the motion of the electrons along the path OQ,
Sx = uxt
Sx = 0.02m
so t = 3.373 x 10-9 s
Sy = 0.5 x v2t2/r
Sy = 8.889 x 10-3m
tanθ = Sy/Sx
θ=23.96 degrees.
This will be the angle AQE as well
so tanθ = AE/QE
from here AE = 0.0267m
So total displacement AF = AE + Sy = 0.0267 + 8.889 x 10-3
AF = 3.56cm
The answer given is 12.87cm