Lorenz guage and equation of continuity

[likephysics]

π²³ ∞ ° → ~ µ ρ σ τ ω ∑ … √ ∫ ≤ ≥ ± ∃ · θ φ ψ Ω α β γ δ ∂ ∆ ∇ ε λ Λ Γ ô

Homework Statement

Show that Lorentz' gauge equation
∇.A = -µ(jωε+σ_e)φ

is the equation of continuity

∇ .Ji = (jωε+σ_e)/ε P(R)

Homework Equations

The Attempt at a Solution

I tried taking curl, div of ampere's law, faraday's law but got nowhere.
Any clue or hint?

 

[gabbagabbahey]

You might start by taking the gradient of each side of the Lorentz Gauge equation, and then maybe taking the curl of each side of the resulting equation after substituting [itex]\mathbf{\nabla}\varphi=-\textbf{E}-\frac{\partial \textbf{A}}{\partial t}[/tex]

 

[malysaad]

Starting from continuity Equation, how to reach Lorenz guage?

I have tried everything, but I failed. Any hint would be appreciated.

You might start by taking the gradient of each side of the Lorentz Gauge equation, and then maybe taking the curl of each side of the resulting equation after substituting [itex]\mathbf{\nabla}\varphi=-\textbf{E}-\frac{\partial \textbf{A}}{\partial t}[/tex]