Lorentz triangle and length contraction perpendicular to propagation

In summary, the conversation discusses the effects of relativity on a moving pole and the concept of aberration of the pole's end. Lorentz's triangle and the Lorentz factor are mentioned, as well as the concept of length contraction. The concept of Penrose-Terrell rotation is also brought up, which accounts for the fact that light reaching our eyes at a given instant from different parts of a moving object will have left the object at different instants. It is noted that Penrose-Terrell rotation has a place in special relativity and is not considered extraneous to it.
  • #1
ANvH
54
0
Consider a pole of 1 light second long in the ##y## direction (the vertical line(s) in the enclosed figure). It is moving in the ##-x## direction. According SR, the pole's length is not contracted because its length is not parallel to the propagation direction. However, given the time of flight of light, a signal from the pole's end will arrive 1 second later than a light signal from the pole's start. Given the pole is moving, one would expect an aberration of the pole's end. In the figure I have drawn a triangle, with the hypothenuse indicating the aberration angle ##\phi##. The horizontal line depicts the speed.

Both triangles in the figure are identical, the labeling of the sides is according to Lorentz's triangle that defines the ##\gamma## factor. The labeling of the sides of the lower triangle are obtained by dividing the labels of the upper triangle by the ##\gamma## factor.

When observing the moving pole in a rest frame one would expect that the hypothenuse is slanted to the left (think of mirror images of these figures). Choosing a frame where the pole is at rest, one would observe (by taking a picture) an aberration as shown in the figure. But SR does not predict this. It would predict no aberration.

Further, a peculiar issue is shown in the figure. The bottom triangle indicates that the vertical line is contracted by the ##\gamma## factor, which is not predicted by SR. The upper triangle does not suggest length contraction of the vertical line (the pole), but shows that the hypothenuse is dilated by the ##\gamma## factor.

I am trying to figure Lorentz's assertion of length contraction that explained the null result of MM and the above is a representation of one the light-arms involved.
 

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  • #3
PeterDonis said:


Thanks for the heads up, but don't you agree that the Lorentz transformation fails to predict this? After all, when moving with the pole, i.e., observing a pole at rest does not require a correction of the time of flight of light, because we can measure the pole's length at will. If we were to allow such a correction then we would define
##t'=t - c^{-1}y##​
##y'=y-ct##​
with a determinant equal to zero. Combining this transformation with the usual Lorentz transformation requires a matrix with two time components and two (##x, y##) spatial components. Reading up on such matrix scenario's is apparently a no, no.

So does the Penrose-Terrell rotation has a place in SR, or is it considered as visual effects extraneous to SR, while SR has nothing to do with optical phenomena?
 
  • #4
ANvH said:
Thanks for the heads up, but don't you agree that the Lorentz transformation fails to predict this?

Fails to predict what? It certainly doesn't fail to predict Penrose-Terrell rotation. Of course, in order to correctly predict that, you need to take into account the fact that the light reaching your eyes at a given instant from different parts of a moving object will have left the object at *different* instants.

ANvH said:
After all, when moving with the pole, i.e., observing a pole at rest does not require a correction of the time of flight of light, because we can measure the pole's length at will.

First of all, if you are at rest relative to the pole, Penrose-Terrell rotation doesn't come into play. Neither do any of the aberration effects you're talking about. So I'm not sure why you're considering that case.

Given that you're at rest relative to the pole, however, you haven't stated things correctly. The correct statement is: you can measure the pole's length if it is at rest relative to you, without having to make corrections for light travel time (for example, by seeing where its ends fall relative to a measuring rod that's at rest relative to you and the pole). But measuring the pole's length in this way is *not* the same as "observing" the pole in the sense of actually looking at the image produced by the light entering your eyes from the pole at a particular instant. The light entering your eyes at a particular instant is always time-delayed if it's coming from a part of the pole that is spatially separated from you: even if you are at rest relative to the pole, you can't be co-located with more than one point along the pole, so light from any other part of the pole is time-delayed when it reaches your eyes.

ANvH said:
If we were to allow such a correction then we would define
##t'=t - c^{-1}y##​
##y'=y-ct##​
with a determinant equal to zero. Combining this transformation with the usual Lorentz transformation requires a matrix with two time components and two (##x, y##) spatial components. Reading up on such matrix scenario's is apparently a no, no.

I have no idea what you're talking about here. Do you have a reference you can give for this transformation, and why it's a "no, no" to read up on it?

ANvH said:
So does the Penrose-Terrell rotation has a place in SR

Certainly. If you want to know what an object moving relativistically actually looks like, as in, what the images entering your eyes at a given instant will look like, Penrose-Terrell rotation is what tells you that.

ANvH said:
or is it considered as visual effects extraneous to SR, while SR has nothing to do with optical phenomena?

No. See above.
 
  • #5
PeterDonis said:
First of all, if you are at rest relative to the pole, Penrose-Terrell rotation doesn't come into play. Neither do any of the aberration effects you're talking about. So I'm not sure why you're considering that case.

When at rest relative to the pole, a light signal at the end of the pole is delayed and therefore there is an aberration if the pole and I are moving with respect to some absolute rest frame. This means that in such a scenario I would know that I am moving with the pole, thanks to the finite speed of light. Is that not correct?

The matrix I constructed for an object at rest. Was trying to combine this with the Lorentz transformation, realizing that a) the determinant is zero, that b) in the particular scenario two time components are required. A while ago I was reading up on multidimensional matrices on one of the wikipedia pages, where it was stated that a 1:3 matrix is stable (1 component for time, 3 components for space). Other combinations involving more than one time components were not stable; can't find the specific page. Don't know why it would be unstable, it was merely expressed as such.
 
  • #6
ANvH said:
When at rest relative to the pole, a light signal at the end of the pole is delayed and therefore there is an aberration if the pole and I are moving with respect to some absolute rest frame.

No. Aberration is relative to the actual observer seeing the light, not relative to some arbitrary frame. If you are at rest relative to the pole, you observe no aberration in light from the pole. An observer that is moving with respect to the pole will see aberration. But if there's no actual observer observing the light. "aberration" is a meaningless concept.

Also, there is no such thing as an "absolute rest frame" in SR.

ANvH said:
This means that in such a scenario I would know that I am moving with the pole, thanks to the finite speed of light.

You would know you were moving with the pole because you can directly measure that you are moving with the pole: zero Doppler shift of light signals between you and the pole, constant round-trip light travel time from you to any point on the pole, etc. You don't need to know what any other frame is doing; in fact you don't even need to *define* a frame. The fact that you are at rest relative to the pole is a direct, frame-independent observable.

ANvH said:
The matrix I constructed for an object at rest. Was trying to combine this with the Lorentz transformation, realizing that a) the determinant is zero, that b) in the particular scenario two time components are required.

I still have no idea what you are talking about here.

ANvH said:
A while ago I was reading up on multidimensional matrices on one of the wikipedia pages, where it was stated that a 1:3 matrix is stable (1 component for time, 3 components for space). Other combinations involving more than one time components were not stable; can't find the specific page.

Then I'm afraid I can't be much help, because none of this makes any sense to me.
 
  • #7
PeterDonis said:
No. Aberration is relative to the actual observer seeing the light, not relative to some arbitrary frame. If you are at rest relative to the pole, you observe no aberration in light from the pole. An observer that is moving with respect to the pole will see aberration. But if there's no actual observer observing the light. "aberration" is a meaningless concept.

Exactly, SR tells you this. However, you do know that after the first Michelson experiment in 1881, Lorentz's remark was that the transverse path should undergo aberration to account for the null result. The M&M paper of 1887 describes this modification in experiment and approach, however, again a null result was obtained.

I respect your answer, but I am not satisfied with it. I think this pole concept introduced here is incompatible with SR. I also think that Lorentz's suggestion after the 1881 experiment is similar to the pole concept. His suggestion was of course way before 1905, before SR, but given Lorentz's high standing in physics, the concept of aberration where the pole and the observer are at rest is certainly not meaningless.

I also think it is unfortunate that you dismiss aberration when at rest to the pole. I think you are missing the point when the pole and the observer are moving. The delay of light arriving at the observer under the condition described is exactly the point Lorentz made in 1881.
 
  • #8
ANvH said:
However, you do know that after the first Michelson experiment in 1881, Lorentz's remark was that the transverse path should undergo aberration to account for the null result. The M&M paper of 1887 describes this modification in experiment and approach, however, again a null result was obtained.

Yes, and all this was well before SR anyway. I'm not sure what you think this is supposed to show.

ANvH said:
I think this pole concept introduced here is incompatible with SR.

I'm not sure what "concept" you're referring to. SR explains the null result of the MM experiment perfectly well, without having to resort to the stuff Lorentz hypothesized. If you're finding something in your description of the pole that seems incompatible with SR, my money is on you misunderstanding something, not on SR being wrong. But I confess I don't understand what you're trying to describe well enough to be able to point out a specific error.

ANvH said:
given Lorentz's high standing in physics, the concept of aberration where the pole and the observer are at rest is certainly not meaningless.

This is an argument from authority and carries no weight here.

ANvH said:
I also think it is unfortunate that you dismiss aberration when at rest to the pole.

I didn't "dismiss" it, I said that aberration is observer-dependent. An observer at rest relative to the pole will see no aberration in the light coming from it; an observer moving relative to the pole will.

ANvH said:
I think you are missing the point when the pole and the observer are moving. The delay of light arriving at the observer under the condition described is exactly the point Lorentz made in 1881.

Delay relative to which observer? I think you're confusing light speed time delay with aberration; they're not the same thing. At least, the standard meaning of "aberration" is not the same as light speed time delay. You may be using "aberration" to mean something other than the standard SR meaning of that word; if so, you should explain exactly what you mean by "aberration", and preferably find a different word to use for it.
 
  • #10
PeterDonis said:
If you're finding something in your description of the pole that seems incompatible with SR, my money is on you misunderstanding something, not on SR being wrong. But I confess I don't understand what you're trying to describe well enough to be able to point out a specific error.

Ok, aberration causes objects to appear to be angled or tilted towards the direction of motion of the observer. I mentioned this in the first post and referred to the triangles you should see as the mirror image of the triangle shown.

The point I make is a reverse aberration, i.e., causes the object to be angled or tilted in the opposite direction of motion. This would occur when both observer and object move with the same speed and direction.

PeterDonis said:
This is an argument from authority and carries no weight here.

But I understand your point here, it is a matter of velocity addition and my scenario and that of Lorentz do not correspond to this.

Edit: The M&M experiment of 1887 to account for this suggestion of Lorentz did not make sense.
 
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  • #12
ANvH said:
Ok, aberration causes objects to appear to be angled or tilted towards the direction of motion of the observer.

Yes, I understand that, but "motion of the observer" here means motion relative to the source. If the observer is at rest relative to the source, there is no aberration.

ANvH said:
I mentioned this in the first post and referred to the triangles you should see as the mirror image of the triangle shown.

I don't understand what the triangle is representing or why you should see a mirror image, under what circumstances?

ANvH said:
The point I make is a reverse aberration, i.e., causes the object to be angled or tilted in the opposite direction of motion. This would occur when both observer and object move with the same speed and direction.

This makes no sense to me (unless it's based on a belief in an "absolute rest frame"--see below), but more importantly, it's inconsistent with actual experimental observations, which show, as I said above, that there is no aberration when the observer and the source are at rest relative to each other.

With regard to "observer and object moving with the same speed and direction", you used the term "absolute rest frame" in an earlier post, and I responded that there is no such thing as an absolute rest frame in SR. I might add that there is also no experimental evidence for any such absolute rest frame. Lorentz apparently believed that there was such a thing, but every proposal he made for experimentally detecting it (of which, IIRC, his proposal about aberration being present when both observer and object were moving with the same speed and direction was one) turned out not to work, i.e., the proposed experiments, when done, gave null results. So if you're trying to argue that Lorentz was right somehow, you aren't going to make much progress here without being able to point at any experiments justifying his view.
 
  • #13
PeterDonis said:
With regard to "observer and object moving with the same speed and direction", you used the term "absolute rest frame" in an earlier post, and I responded that there is no such thing as an absolute rest frame in SR. I might add that there is also no experimental evidence for any such absolute rest frame. Lorentz apparently believed that there was such a thing, but every proposal he made for experimentally detecting it (of which, IIRC, his proposal about aberration being present when both observer and object were moving with the same speed and direction was one) turned out not to work, i.e., the proposed experiments, when done, gave null results. So if you're trying to argue that Lorentz was right somehow, you aren't going to make much progress here without being able to point at any experiments justifying his view.

In essence I already agreed with this when I responded to your previous post.
 
  • #14
ANvH said:
ghwellsjr said:
ANvH: didn't we cover essentially this same topic for in-line scenarios over a month ago?

https://www.physicsforums.com/showthread.php?t=745692
No, certainly not, this is different, but it is solved now.
I'm not sure it has been solved. In that thread, you were trying to define a Doppler with a moving source and no observer and I see you trying to do the same thing with regard to aberration in this thread. Otherwise, why are you insisting on the source moving relative to the frame?

EDIT: To clarify: Aren't you trying to define aberration as something that happens with a moving source with regard to the frame and then you define a reverse aberration that applies from the frame to the moving observer so that the two cancel out leaving the observer with the same observation that he would get if both the source and observer were not moving?
 
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  • #15
ANvH said:
In essence I already agreed with this when I responded to your previous post.

Agreed with what? That Lorentz's proposals were disproved by experiment? Then I don't understand what the point of this thread is, since as far as I can tell, your "triangle diagram" in the OP was based on Lorentz's disproved proposals.
 

Related to Lorentz triangle and length contraction perpendicular to propagation

1. What is the Lorentz triangle?

The Lorentz triangle is a geometric representation of the relationship between the measurements of length, time, and velocity in special relativity. It is named after the Dutch physicist Hendrik Lorentz who first described it.

2. How does the Lorentz triangle relate to length contraction?

The Lorentz triangle illustrates how the length of an object appears to decrease when it is moving at high speeds. This phenomenon is known as length contraction and is a key concept in special relativity.

3. What is length contraction perpendicular to propagation?

Length contraction perpendicular to propagation refers to the shortening of an object in the direction perpendicular to its motion. This is in contrast to length contraction parallel to the direction of motion, which is known as the Lorentz contraction or the Fitzgerald-Lorentz contraction.

4. How does length contraction perpendicular to propagation affect measurements?

Length contraction perpendicular to propagation has a significant impact on measurements taken in moving reference frames. It causes the physical length of objects to appear shorter and can also affect the measurement of time intervals.

5. Is length contraction perpendicular to propagation a real physical effect?

Yes, length contraction perpendicular to propagation is a real physical effect that has been observed in experiments and is a fundamental aspect of special relativity. It is essential to understand and account for in order to accurately describe and predict the behavior of objects moving at high speeds.

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