- #1
Dorian Black
- 12
- 0
Hi,
A capacitor has both its terminals connected together using a wire in a rather lengthy circular fashion, hence acting as a significant inductance.
If the area encircled by this 'circuit' is subjected to a linearly rising magnetic field (B=k x t) where k is a constant, the emf induced -due to this external magnetic source- is a constant value proportional to k.
A current will run and consequently begin to charge the capacitor. My question; will this charging process continue for as long as the external magnetic field is linearly rising, or will it take the capacitor up to a voltage related to (k) and then reach an equilibrium? I'm aware that the current that runs in the circuit will affect the magnetic field crossing it and hence affect the process, but my question is still the same. Does the capacitor's voltage only rise to some certain value or would it carry on doing so until breakdown occurs in the dielectric?
Thanks
A capacitor has both its terminals connected together using a wire in a rather lengthy circular fashion, hence acting as a significant inductance.
If the area encircled by this 'circuit' is subjected to a linearly rising magnetic field (B=k x t) where k is a constant, the emf induced -due to this external magnetic source- is a constant value proportional to k.
A current will run and consequently begin to charge the capacitor. My question; will this charging process continue for as long as the external magnetic field is linearly rising, or will it take the capacitor up to a voltage related to (k) and then reach an equilibrium? I'm aware that the current that runs in the circuit will affect the magnetic field crossing it and hence affect the process, but my question is still the same. Does the capacitor's voltage only rise to some certain value or would it carry on doing so until breakdown occurs in the dielectric?
Thanks