- #1
bishy
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Homework Statement
An LC circuit starts at t=0 with its 2000 microF capacitor at its peak voltage of
14V. At t=35 ms the voltage has dropped to 8.5 V.
a) What will be the peak current?
b) At what time will the peak current occur?
c) What must be the value of the inductor in the circuit?
The Attempt at a Solution
the answers I found are:
a) 1.73*10^-1 A
b) 7.05 s
c) 6.474 H
I've attached the work in two pictures, should be able to zoom into it if you are having problems reading it. I can do it easy doing windows picture media Is this right? Also, it seems like a did a whole lot of work when something probably really obvious that I am not seeing could have been used. Is there a shorter more efficient way to solving this problem?
edit - well attaching isn't going to work, the files are here than:
http://tnaag.org/test.jpg
http://tnaag.org/test3.jpg
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