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flannabhra
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Homework Statement
If you measure the resistance of the three lightbulbs (independently) and get the following values. What is the equivalent total resistance of the circuit, and it’s uncertainty.
[tex] R_1 = (50 \pm 7) \Omega, \ \ R_2 = (720 \pm 30) \Omega, \ \ R_3 = 140 \pm 20) \Omega [/tex]
Now you connect a bare wire (with negligible internal resistance) between to the left and right of L2 respectively in the circuit diagram. What will happen to the brightness of each bulb (i.e. will it increase, decrease, or remain the same)? Justify your results by finding the power of each light bulb in terms of ∆Vbat.
Homework Equations
[tex] \frac{1}{R_{eq}} = \frac{1}{R_{L2}} + \frac{1}{0} [/tex]
The Attempt at a Solution
[tex] \frac{1}{R_{eq}} = \frac{1}{720 \ \Omega} + \frac{1}{0} [/tex]
[tex] R_{eq} = 0 \Omega [/tex]
Knowing that the resistance in the top half of the parallel component of this circuit is now 0, does that imply that the current, I1, into the parallel component is now equivalent to I2, the current into L2 and the wire? I.E. is there any power going through L3 after the wire is connected?
Thank you in advance!