- #1
SANGEETAMILIND
- 10
- 0
In an SHM, the only force that should be acting, that is the net force should be the restoring force F, by definition...
F = -kx
For example there is a massless spring of spring constant k attached to the ceiling and there is a body of mass m hung at it and avoiding all kinds of friction...
Due to the weight of the body the equilibrium mean position will be shifted...
numerically it would become
xo = (mg/k)
{considering the the original mean position to be 0}
angular frequency and time period would still be the same as in the SHM motion performed by the spring if it were kept horizontally at natural length.
But by definition of Simple Harmonic Oscillators
F= -kx should be the only force... and in the vertically hung spring mass system 'mg' is also acting, not withstanding that the motion is exactly like the SHM with a different equilibrium position.
Would it still be considered as a simple harmonic oscillator?
F = -kx
For example there is a massless spring of spring constant k attached to the ceiling and there is a body of mass m hung at it and avoiding all kinds of friction...
Due to the weight of the body the equilibrium mean position will be shifted...
numerically it would become
xo = (mg/k)
{considering the the original mean position to be 0}
angular frequency and time period would still be the same as in the SHM motion performed by the spring if it were kept horizontally at natural length.
But by definition of Simple Harmonic Oscillators
F= -kx should be the only force... and in the vertically hung spring mass system 'mg' is also acting, not withstanding that the motion is exactly like the SHM with a different equilibrium position.
Would it still be considered as a simple harmonic oscillator?
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