- #1
jarrodtuck1
- 2
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I was wondering if anyone could help me with some homework.
I have the equation y = [(e^x)-3]/[(e^x)+1] and need to find its inverse.
I take the natural ln of both sides and get :
lny = (x-3)/(x+1)
Then I multiple the denominator to the other side and get
lny(x+1) = x -3
Then i just add three to both sides and switch the x and y's to get the inverse
y = lnx (x+1) +3
My teacher got the answer:
x = ln [ (3+x)/(1-x)]
How??
I have the equation y = [(e^x)-3]/[(e^x)+1] and need to find its inverse.
I take the natural ln of both sides and get :
lny = (x-3)/(x+1)
Then I multiple the denominator to the other side and get
lny(x+1) = x -3
Then i just add three to both sides and switch the x and y's to get the inverse
y = lnx (x+1) +3
My teacher got the answer:
x = ln [ (3+x)/(1-x)]
How??