Internal-Combustion Engine Prototypes Ranking Task?

In summary, when ranking these engines by their designed power output, the order from highest to lowest is: P1 > P6 > P3 > P5 > P4 > P2. The thermal efficiency was not taken into account for this ranking.
  • #1
cupcake
76
0

Homework Statement




Rank these engines on the basis of their designed power output and their thermal efficiency.

1) Qin = 3000 J, Qout = 1500 J, f=150 Hz.
2) Qin = 4000 J, Qout = 3000 J, f=50 Hz.
3) Qin = 1000 J, Qout = 200 J, f=200 Hz.
4) Qin = 2000 J, Qout = 500 J, f=50 Hz.
5) Qin = 2000 J, Qout = 1000 J, f=100 Hz.
6) Qin = 1500 J, Qout = 500 J, f=200 Hz.

Homework Equations



P=Work/t, and Work=Qin-Qout

The Attempt at a Solution



I calculated the power output using the above formulas, where t=1/f, but I don't know why my answers are wrong... this is mastering physics question :(
 
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  • #2
cupcake said:

Homework Statement




Rank these engines on the basis of their designed power output and their thermal efficiency.

1) Qin = 3000 J, Qout = 1500 J, f=150 Hz.
2) Qin = 4000 J, Qout = 3000 J, f=50 Hz.
3) Qin = 1000 J, Qout = 200 J, f=200 Hz.
4) Qin = 2000 J, Qout = 500 J, f=50 Hz.
5) Qin = 2000 J, Qout = 1000 J, f=100 Hz.
6) Qin = 1500 J, Qout = 500 J, f=200 Hz.

Homework Equations



P=Work/t, and Work=Qin-Qout

The Attempt at a Solution



I calculated the power output using the above formulas, where t=1/f, but I don't know why my answers are wrong... this is mastering physics question :(
Perhaps you could show us your answers. What is your equation for thermal efficiency? Are you taking that into account?

AM
 
  • #3
so,

1) W1=1500 P1=W1/t= 225000
2) W2=1000 P2=W2/t= 50000
3) W3=800 P3=W3/t= 160000
4) W4=1500 P4= 75000
5) W5=1000 P5=100000
5) W6=1000 P6=200000

so, the rank from the largest to the smaller will be, P1 > P6 > P3 > P5 > P4 > P2

thermal efficiency formula is 1-Qin/Qout, that one is for the next question (arrange by basis of thermal efficiency)
 
  • #4
cupcake said:
so,

1) W1=1500 P1=W1/t= 225000
2) W2=1000 P2=W2/t= 50000
3) W3=800 P3=W3/t= 160000
4) W4=1500 P4= 75000
5) W5=1000 P5=100000
5) W6=1000 P6=200000

so, the rank from the largest to the smaller will be, P1 > P6 > P3 > P5 > P4 > P2

thermal efficiency formula is 1-Qin/Qout, that one is for the next question (arrange by basis of thermal efficiency)
Looks right. What is the problem?

AM
 
  • #5
Andrew Mason said:
Looks right. What is the problem?

AM

I don't know..masteringphysics said it's wrong :(
 

Related to Internal-Combustion Engine Prototypes Ranking Task?

1. What is an internal-combustion engine prototype?

An internal-combustion engine prototype is a working model of a new or improved version of an internal-combustion engine. It is used for testing and evaluating the design before mass production.

2. How are internal-combustion engine prototypes ranked?

Internal-combustion engine prototypes are typically ranked based on their performance, efficiency, emissions, and reliability. These factors are evaluated through rigorous testing and comparison to existing models.

3. What is the purpose of ranking internal-combustion engine prototypes?

The purpose of ranking internal-combustion engine prototypes is to identify the most promising designs and determine which ones should be further developed and potentially brought to market. It also helps to identify any flaws or weaknesses in the prototypes that need to be addressed.

4. How do scientists determine the ranking of internal-combustion engine prototypes?

Scientists determine the ranking of internal-combustion engine prototypes by conducting various tests and measurements, such as horsepower, torque, fuel efficiency, emissions, and durability. They also take into account feedback from experts and potential users.

5. What is the significance of the ranking task for internal-combustion engine prototypes?

The ranking task for internal-combustion engine prototypes is significant because it allows scientists and engineers to identify the most promising designs and make improvements to existing models. This can lead to more efficient and environmentally-friendly engines, as well as advancements in technology and transportation. It also helps to determine which prototypes are worth investing resources and time into for further development.

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