Interesting Electric Field and Spring Problemf

In summary, the problem involves a block with mass m and charge +Q connected to an insulating spring with constant k, situated on a frictionless, insulating horizontal track and immersed in a uniform electric field of magnitude E. The block is released from rest when the spring is unstretched at x = 0. The problem asks for (a) the maximum amount the spring expands, (b) the equilibrium position of the block, (c) the block's motion being simple harmonic and its period, and (d) the answer to (a) if the coefficient of kinetic friction between the block and surface is mew K. The solution for (a) is 2QE/k, which can be derived by considering the relationship between
  • #1
caesius
24
0

Homework Statement


A block having mass m and charge +Q is connected to an insulating spring having constant k. The block lies on a frictionless, insulating horizontal track, and the system is immersed in a uniform electric field of magnitude E as shown in the diagram. If the block is released from rest when the spring is unstretched (at x = 0),

(a) by what maximum amount does the spring expand?
(b) what is the equilibrium position of the block
(c) show that the block's motion is simple harmonic and determine its period
(d) repeat (a) assuming that the coefficient of kinetic friction between the block and the surface is mew K.

http://img513.imageshack.us/img513/3959/physprobzm4.png

Homework Equations


a few, F = qE = ma = -kx

The Attempt at a Solution



I'm only starting to attempt part (a), the block has a force QE to the right and a restoring force kx to the left.

So I equated the forces thus: QE = kx and solved for x to obtain x = QE/k.

This isn't the solution for (a), but it is for (b). The solution for (a) is 2QE/k

It's driving me crazy trying to find where the 2 came into calculations. Working backwards from (b) I see that the equilibrium position is half of the maximum expansion. But how so?
 
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  • #2
Right, that's the answer for B because at the equilibrium position, the restoring force of the spring is equal to the electric force. That's why at equilibrium, Fnet is 0 so the acceleration of the block is also zero.

For part A, consider the relationship between the potential energy of the spring at the point of furthest expansion and the work the electric force must do to get the block to that point.
 
  • #3


I can offer a possible explanation for the discrepancy in your calculations. It is possible that the diagram and problem statement are not accurately representing the scenario. For example, the diagram shows the block being released from the origin (x=0) but the problem statement mentions the block being released when the spring is unstretched (at x=0). These two scenarios could result in different equilibrium positions and maximum expansions.

In addition, the presence of the electric field and charge on the block could also affect the equilibrium position and maximum expansion. It is possible that the electric field is not uniform or that the charge on the block is not accurately represented in the diagram. These factors could also contribute to the discrepancy in your calculations.

As a scientist, it is important to carefully consider all factors and variables in a problem before coming to a conclusion. In this case, it may be helpful to review the problem statement and diagram for any discrepancies or uncertainties, and to double check your calculations to ensure accuracy.
 

Related to Interesting Electric Field and Spring Problemf

1. What is an electric field and how does it interact with a spring?

An electric field is a region of space in which an electric charge experiences a force. When a charged particle is placed in an electric field, it will experience a force in the direction of the field lines. This force can cause the spring to stretch or compress depending on the direction of the field.

2. Can you give an example of an interesting electric field and spring problem?

One example of an interesting electric field and spring problem is the charge on a spring. In this problem, a charged particle is placed at one end of a spring while the other end is attached to a fixed point. The electric field from the charged particle will cause the spring to stretch or compress, resulting in a new equilibrium position for the spring.

3. How do you calculate the force exerted on the spring by the electric field?

The force exerted on the spring by the electric field can be calculated using Coulomb's law. This law states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

4. How does the strength of the electric field affect the behavior of the spring?

The strength of the electric field has a direct impact on the behavior of the spring. A stronger electric field will result in a greater force being exerted on the spring, causing it to stretch or compress more. Conversely, a weaker electric field will result in a smaller force and less movement of the spring.

5. Can you manipulate the electric field to change the behavior of the spring?

Yes, the behavior of the spring can be manipulated by changing the strength or direction of the electric field. By changing the charge of the particle or its position relative to the spring, the electric field can be altered and therefore change the force exerted on the spring. This can result in changes in the spring's equilibrium position or the amount of stretching or compression.

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