Integrating Sin(6θ): Am I Close?

[duki]

Homework Statement

[tex]\int\sin(6\theta) d\theta[/tex]

Homework Equations

The Attempt at a Solution

[tex]\int6\cos6\theta[/tex]

Am I close?

 

[Feldoh]

If it helps do a u-sub where u=6theta

Or you could think of it like this:

If we take the derivative of [tex]\frac{d}{d \theta}(-cos(\theta)) = sin(\theta)[/tex]. That's sort of like the anti-derivative which you seek.

If we take the derivative of [tex]\frac{d}{d \theta}(-cos(6 \theta)) = 6sin(6 \theta)[/tex].

So from there it's easy to see that[tex]\int\sin(6\theta) d\theta = \frac{-cos(6\theta)}{6}[/tex]

 

[duki]

errr...

[tex]\frac{-\cos6\theta}{6}[/tex]

 

[duki]

thanks :)

 

[Feldoh]

Yeah looks right^^