- #1
Chandasouk
- 165
- 0
I have solutions for 2 problems but they are different from the ones my book provides. This may be due to some simplification they chose to do, but I am uncertain.
1) dy/dx = x2/y
ydy = x2dx
Integrate both sides and you get
y2/2 = x3/3 + C
My book gave 3y2 - 2x3 = C
2) dy/dx = x2 / y(1+x3)
y(1+x3)dy = x2dx
ydy = x2/(1+x3) dx
Integrating both sides, I got
y2/2 = 1/3*ln(1+x3) + C
but my book gave
3y2-2ln(1+x3) = C
1) dy/dx = x2/y
ydy = x2dx
Integrate both sides and you get
y2/2 = x3/3 + C
My book gave 3y2 - 2x3 = C
2) dy/dx = x2 / y(1+x3)
y(1+x3)dy = x2dx
ydy = x2/(1+x3) dx
Integrating both sides, I got
y2/2 = 1/3*ln(1+x3) + C
but my book gave
3y2-2ln(1+x3) = C