- #1
cliowa
- 191
- 0
Dear community
I'm trying to get a grip on this integral:
[tex]\int \frac{\sqrt{1-x}}{\sqrt{x}-1} dx[/tex].
I tried substituting [tex]x=\sin^{2}(u)[/tex], which leaves me (standing) with
[tex]\int \frac{\sin(u)\cos^{2}(u)}{\sin(u)-1} du[/tex].
But I just can't solve it, no matter which way I try.
I would be thankful for every kind of hint/explanation.
Best regards...Cliowa
I'm trying to get a grip on this integral:
[tex]\int \frac{\sqrt{1-x}}{\sqrt{x}-1} dx[/tex].
I tried substituting [tex]x=\sin^{2}(u)[/tex], which leaves me (standing) with
[tex]\int \frac{\sin(u)\cos^{2}(u)}{\sin(u)-1} du[/tex].
But I just can't solve it, no matter which way I try.
I would be thankful for every kind of hint/explanation.
Best regards...Cliowa