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bearhug
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A 32.0 kg wheel, essentially a thin hoop with radius 1.20 m is rotating at 280 rev/min. It must be brought to a stop in 15.0s (a) How much work must be done to stop it?
t=15.0s
m=32.0kg
r=1.20m
ω= 29.3 rad/s after conversion
I need to find W
I think I need to find torque in order to find work. Would torque τ=Fr
F=ma so F=32.0kg(9.8m/s^2)= 313.6 N τ=313.6(1.20m)=376.3
Is this the right approach, if it is what equation should I use to find W. The equation in my book is an integral does that sound right? Thanks
t=15.0s
m=32.0kg
r=1.20m
ω= 29.3 rad/s after conversion
I need to find W
I think I need to find torque in order to find work. Would torque τ=Fr
F=ma so F=32.0kg(9.8m/s^2)= 313.6 N τ=313.6(1.20m)=376.3
Is this the right approach, if it is what equation should I use to find W. The equation in my book is an integral does that sound right? Thanks