- #1
Gale
- 684
- 2
In a region of fair weather, the electric field is found to be vertically down. At an altitude of 400m E=20 N/C at 200m E=90 N/C. Find the net charge contained in a cube 200m on and edge, with horizontal faces at altititudes of 200m and 400m.
I wasn't sure where to start so i used coulumbs law and plugged in the altitudes and electric fields.
[tex]20=\frac{kQ}{400^2}[/tex] and [tex]90=\frac{kQ}{200^2}[/tex]
Then i found the difference and got .4e6. I thought that would be the answer maybe, but its mult choice and that's not one of them. So now I'm not really sure what to do...
I wasn't sure where to start so i used coulumbs law and plugged in the altitudes and electric fields.
[tex]20=\frac{kQ}{400^2}[/tex] and [tex]90=\frac{kQ}{200^2}[/tex]
Then i found the difference and got .4e6. I thought that would be the answer maybe, but its mult choice and that's not one of them. So now I'm not really sure what to do...