How Is F_p/F^2_p Isomorphic to (T_p(M))^* in Smooth Manifolds?

In summary, the conversation discusses the problem of showing that F_p/F^2_p is isomorphic to (T_p(M))^star using the first isomorphism theorem in algebra. It is mentioned that this theorem is valid for groups, but since every vector space has a group structure, it applies in this case. The solution is found by showing that ker(phi)=F²_p, and it is clarified that the map in question is linear.
  • #1
seydunas
39
0
Hi,

I want to ask a problem from Lee ' s book Introduction to Smooth Manifolds: Let F_p denote the subspace of C^\inf(M) consisting of smooth functions that vanish at p and let F^2_p be the subspace of F_p spanned by functions fg for some f,g \in F_p. Define a map \phi: F_p-----> (T_p(M))^star by f-----> df_p Show that F_p/F^2_p is isomorphic to (T_p(M))^star

Thanks...
 
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  • #2
By the first isomorphism theorem in algebra, you only need to show that ker(phi)=F²_p.
 
  • #3
I can see why ker(phi)=F²_p. But the first isomorphism theorem of algebra is valid for groups, right? Ohh yes, every vector space has a group structure under addition. So, we are done.
 
  • #4
Sorry, our map is linear. So this is true for vector spaces. Now i understood everything.
 
  • #5


I would like to address this problem by first defining some relevant terms. A smooth manifold is a mathematical concept that describes a space that is locally similar to Euclidean space. It is an important tool in many areas of mathematics and physics, including differential geometry and general relativity. In this context, C^\inf(M) refers to the space of smooth functions on the manifold M, and (T_p(M))^star is the dual space of the tangent space at point p on the manifold.

Now, let's consider the given map \phi: F_p \rightarrow (T_p(M))^star, where f \in F_p is mapped to its differential df_p. This map is well-defined because f vanishes at p, so df_p is a linear map from the tangent space to the real numbers. We can also see that \phi is a surjective map, since any linear map from the tangent space to the real numbers can be written as df_p for some smooth function f.

Next, we want to show that F_p/F^2_p is isomorphic to (T_p(M))^star. This means that there exists a bijective map between these two spaces that preserves their algebraic structure. To prove this, we can define a map \psi: F_p/F^2_p \rightarrow (T_p(M))^star by \psi([f]) = df_p, where [f] is the equivalence class of f in the quotient space. This map is well-defined because if [f] = [g], then f-g \in F^2_p, which means df_p = dg_p. It is also easy to see that \psi is a bijection, since it has an inverse given by \phi.

Moreover, we can show that \psi preserves the algebraic structure by showing that \psi([f+g]) = d(f+g)_p = df_p + dg_p = \psi([f]) + \psi([g]) and \psi([af]) = d(af)_p = adf_p = a\psi([f]), where a is a scalar. This proves that \psi is a linear map, and thus, F_p/F^2_p is isomorphic to (T_p(M))^star.

In conclusion, we have shown that the quotient space F_p/F^2_p is isomorphic to the dual space (T_p(M))^star by defining a map \psi that preserves the
 

Related to How Is F_p/F^2_p Isomorphic to (T_p(M))^* in Smooth Manifolds?

What is a smooth manifold according to Lee 6.7?

A smooth manifold is a topological space that locally looks like Euclidean space, meaning that for every point on the manifold, there exists a neighborhood that is homeomorphic to an open subset of Euclidean space. Additionally, the transition maps between different neighborhoods must be smooth, meaning they have infinitely many continuous derivatives.

What is the difference between a smooth manifold and a topological manifold?

A smooth manifold is a topological manifold with the additional requirement that it is equipped with a smooth structure, meaning that it has a collection of charts that satisfy certain compatibility conditions. This allows for the definition of smooth functions and the ability to do calculus on the manifold.

What are charts and atlases in the context of smooth manifolds?

Charts are local coordinate systems on a manifold that allow us to describe points and vectors in terms of coordinates. An atlas is a collection of charts that cover the entire manifold and are compatible with each other, meaning that the transition maps between different charts are smooth.

What is the significance of smooth maps between smooth manifolds?

Smooth maps are functions between smooth manifolds that preserve the smooth structure, meaning that they map smooth points to smooth points. They allow us to study the relationship between different manifolds and are an important tool in differential geometry and topology.

How are tangent spaces defined on a smooth manifold?

Tangent spaces on a smooth manifold are defined as the set of all derivations at a given point. A derivation is a linear map that satisfies the Leibniz rule, which allows for the definition of directional derivatives and tangent vectors on the manifold. Tangent spaces are important for understanding the geometry and calculus of smooth manifolds.

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