How High Does a Coin Tossed Straight Up Reach?

[student54321]

Homework Statement

A coin tossed straight up into the air takes
2.75 s to go up and down from its initial
release point 1.30 m above the ground.

What is its maximum height?

Homework Equations

The Attempt at a Solution

I seriously have no clue how to do this problem. I really need a detailed explanation with steps. I'm sorry if this doesn't abide by your question standards, but I really mean I have 0 idea how to solve this problem, and I really need some help.


Thanks.

 

[student54321]

can anyone help?

 

[Rayquesto]

its 1.30 + V0^2/2g

since V^2=V0^2 + 2g(ay) where the max height is when V=0

 

[Rayquesto]

where V0=g(2.75/2) since V= V0 + gt where V=0m/s since you are accounting for the time it takes and the velocity at the point it goes its max height.

 

[rwisz]

Hello there,

No worries, I am here to help you solve this problem. Let's start by breaking down the information given in the problem.

First, we know that the coin was tossed straight up into the air. This means that the initial velocity (Vi) of the coin is 0 m/s because it is only moving in the vertical direction.

Next, we are given the time it takes for the coin to go up and down - 2.75 seconds. This is the total time it takes for the coin to reach its maximum height and then return to its initial position.

Now, we know that the acceleration due to gravity (g) is -9.8 m/s^2 (negative sign indicates that it is acting in the downward direction).

Using the kinematic equation, we can find the maximum height (h) of the coin:

h = Vi*t + (1/2)*g*t^2

Since Vi = 0, the equation simplifies to:

h = (1/2)*g*t^2

Plugging in the values we have:

h = (1/2)*(-9.8 m/s^2)*(2.75 s)^2

h = (1/2)*(-9.8 m/s^2)*(7.5625 s^2)

h = -36.6625 m

Since the maximum height cannot be negative, we can take the absolute value of this answer to get the actual value:

h = | -36.6625 m | = 36.6625 m

Therefore, the maximum height of the coin is 36.6625 meters. I hope this helps you understand how to approach and solve this type of problem. Let me know if you have any further questions. Good luck!