- #1
Beanie
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Homework Statement
A particle travels between two parallel ver- tical walls separated by 25 m. It moves to- ward the opposing wall at a constant rate of 9.2 m/s. It hits the opposite wall at the same height.
The acceleration of gravity is 9.8 m/s2 .
(IMAGE FOR CLARIFICATION ATTACHED)
a) What will be its speed when it hits the opposing wall?
b) At what angle with the wall will the particle strike?
Homework Equations
Vf=vi+at
d=vit=.5at^2
vf^2=Vi^2+2ad
The Attempt at a Solution
I've tried this problem (a) many times in many different ways, but continue to get it wrong. I have not yet been able to do problem (b) because of the lack of information (I need to complete a to do b)
Attempts:
The first way I tried was to find the time and then plug it into the second equation described above using d=25, t=2.7, a=-9.8. This resulted in a velocity of 22.52m/s. However this velocity is wrong.
The second way I tried was to find t (same as above) and then use Vx=9.2 as well as t=2.7 to calculate Vy. I found this to be 26.62. I then used the pythagorean theorem using Vx and Vy to find V. My final answer was 28.164m/s. This velocity answer was also wrong.
Any suggestions on where I am going wrong? Are there any other ways of calculating velocity?