Right. You have that already done in your first post. (Just change R to r in your equation for E.)kasse said:And outside the ball? I would expext the field to decrease with increasing r, not be constant...
kasse said:Homework Statement
A metal ball with radius R = 0,6 m is charged with Q = 0.15 nC. Find the electrical field as function of the distance r from the center of the ball.
The Attempt at a Solution
Gauss law:
Q = e0*E(r)*A = e0*E(r)*4*pi*R^2
which gives
E(r) = Q / e0*4*pi*R^2
I know that inside the ball, the field will be 0. But obviously this is not a function of r...Am I on the right track?
Gauss's law is a fundamental principle in electromagnetism that relates the electric flux through a closed surface to the net electric charge enclosed by that surface.
Gauss's law applies to any closed surface, including a metal ball. The electric flux through the surface of the ball is directly proportional to the net charge enclosed by the ball.
Gauss's law allows us to calculate the electric field at a point by considering the charge distribution around that point. This simplifies the calculation of electric fields in complex systems and is a powerful tool in understanding the behavior of electric fields.
A metal ball is a useful example in understanding Gauss's law because it has a uniform charge distribution on its surface and is a closed surface, making it easy to apply the law. It also has practical applications in electrical systems, such as in lightning rod design.
Yes, Gauss's law can be applied to any closed surface, regardless of the material it is made of. It is a general principle that applies to all electric fields and charge distributions.