- #1
karush
Gold Member
MHB
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$$\displaystyle y^\prime +(1/x)y = 3\cos 2x, \quad x>0$$
first how do you get $u(x)$ from this
first how do you get $u(x)$ from this
karush said:$$\displaystyle y^\prime +(1/x)y = 3\cos 2x, \quad x>0$$
first how do you get $u(x)$ from this
MarkFL said:\(\displaystyle \mu(x)=\exp\left(\int \frac{1}{x}\,dx\right)=?\)
karush said:$$\displaystyle\mu(x)
=\exp\left(\int \frac{1}{x}\,dx\right)=e^{\ln{x}}=x$$
ok hopefully
ill funish this tomro
the latex is too hard to deal with on a tablet
MarkFL said:Yes, your integrating factor is correct. (Yes)
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