How Do You Calculate Interference Fringes in a Double Slit Experiment?

In summary, a laser beam with a wavelength of 694 nm is incident on two slits 0.100 mm apart. The distance between adjacent bright interference fringes on a screen 5.00 m away from the slits can be calculated using the equation y=L(mλ/d), where L is the distance to the screen, m is the order of the fringe, λ is the wavelength, and d is the distance between the slits. The correct distance between adjacent fringes is 3.47 × 10–2 m.
  • #1
roam
1,271
12

Homework Statement



A laser beam ( λ = 694 nm) is incident on two slits 0.100 mm apart. Approximately how far apart (in m) will the bright interference fringes be on the screen 5.00 m from the double slits?

Homework Equations



[tex]y=L\left( \frac{m \lambda}{d} \right)[/tex]

The Attempt at a Solution



[tex]y_{m+1}-y_m = L \left(\frac{(m+1)\lambda}{d} \right) - L \left( \frac{m \lambda}{d}\right)[/tex]

[tex]= L\frac{\lambda}{d}= 5 \left( \frac{694}{1 \times 10^{-4} m} \right)[/tex]

=34700000

So I got the distance between adjacent fringes to be 34700000 which is a very huge number. But the right answer must be 3.47 × 10–2. Any help is appreciated.
 
Physics news on Phys.org
  • #2
For one thing, the wavelength is 694 nm, not 694 m. (nm = nanometer)
 

Related to How Do You Calculate Interference Fringes in a Double Slit Experiment?

1. What is light wave interference?

Light wave interference refers to the phenomenon where two or more light waves interact with each other, resulting in a change in the overall amplitude (brightness) of the light. This can occur when two or more light waves pass through the same medium or when they meet at a point in space.

2. What causes light wave interference?

Light wave interference is caused by the superposition of two or more light waves. This means that the waves add together, resulting in areas of increased or decreased amplitude, depending on their relative phase difference.

3. What is the difference between constructive and destructive interference?

Constructive interference occurs when two or more waves have a phase difference that results in their amplitudes adding together to create a larger overall amplitude. This results in a brighter area. Destructive interference occurs when two or more waves have a phase difference that results in their amplitudes canceling each other out, creating a darker area.

4. How is light wave interference used in everyday life?

Light wave interference is used in many everyday applications, including anti-reflective coatings on glasses and camera lenses, optical filters, and holograms. It is also used in technologies such as interferometry, which is used in the measurement of tiny distances, and in fiber optics for data transmission.

5. Can light wave interference occur in vacuum?

No, light wave interference cannot occur in a vacuum. Interference requires the presence of a medium for the light waves to interact with. In a vacuum, there is no medium for the light waves to pass through or interact with, so interference cannot occur.

Similar threads

  • Introductory Physics Homework Help
Replies
3
Views
580
  • Introductory Physics Homework Help
Replies
8
Views
1K
  • Introductory Physics Homework Help
Replies
8
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
3K
Replies
4
Views
474
  • Introductory Physics Homework Help
Replies
3
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
2K
Replies
5
Views
1K
Replies
3
Views
1K
Back
Top