- #1
neelakash
- 511
- 1
Homework Statement
I got stuck to this problem:
To prove that (x p)^2 is not equal to (x)^2 (p)^2
where x and p are position and mometum operator in QM.
Homework Equations
The Attempt at a Solution
I approached this way:
Two operators A and B are equal iff Af=Bf for all f
So,here {(x p)^2 - (x)^2 (p)^2}f=0
Since this is valid for all f, we must have {(x p)^2 - (x)^2 (p)^2}=0
In other words, [(x p)^2 , (x)^2 (p)^2 ]=0
But I could not disprove this commutator.Calculations are big and after some steps I doubt whether this might at all be the correct way.
Can anyone please give some hint?