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chicagobears34
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Calculating friction force on a truck on an incline?
A 4200kg truck is parked on a 20 degree slope.
How big is the friction force on the truck? The coefficient of static friction between the tires and the road is 0.90.
F=ma
Ff=mu*m*a
Friction Force on the truck is (4200kg*9.81m/s^2 * .90) = 37081.8N
since it's on an incline I am supposed to do 37081.8 * sin20?
so the answer would be 12682.7N but that is wrong
I also tried doing 37081.8 * cos20 which is 34845.5N which is also wrong
Please help me! Idk what I am doing wrong
Homework Statement
A 4200kg truck is parked on a 20 degree slope.
How big is the friction force on the truck? The coefficient of static friction between the tires and the road is 0.90.
Homework Equations
F=ma
Ff=mu*m*a
The Attempt at a Solution
Friction Force on the truck is (4200kg*9.81m/s^2 * .90) = 37081.8N
since it's on an incline I am supposed to do 37081.8 * sin20?
so the answer would be 12682.7N but that is wrong
I also tried doing 37081.8 * cos20 which is 34845.5N which is also wrong
Please help me! Idk what I am doing wrong
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