Homework Task: Find the power of water

[besfort]

Homework Statement

Find the power of the water if it falls from the height (h= 20m), for every minute falls 80m^3 (Volume=80m³).

Homework Equations

P=A/t
W = mg
A = Fh
P= Fv

The Attempt at a Solution

I attempted to find the mass first, but I couldn't find any formula to do so.

 

[berkeman]

Homework Statement

Find the power of the water if it falls from the height (h= 20m), for every minute falls 80m^3 (Volume=80m³).

Homework Equations

P=A/t
W = mg
A = Fh
P= Fv

The Attempt at a Solution

I attempted to find the mass first, but I couldn't find any formula to do so.

1cc of water weighs 1 gram. So a liter of water weighs a kilogram. That should get you to the answer.

 

[besfort]

If 80m^3 = 80000l, then that means the mass is 80000kg, aye?

 

[rock.freak667]

If 80m^3 = 80000l, then that means the mass is 80000kg, aye?

Right so you have 80,000 kg falling per minute. How much kg per second is that? Hence how much Newtons per second is that?

Remember that Power = Rate at which work is done = Force*distance/Time

 

[Nickie]

Then, I realized that the mass is not necessary to find the power of water. Instead, we can use the formula P= Fv, where P is power, F is force, and v is velocity. Since we know the height (h=20m) and the volume (V=80m^3) of water that falls in one minute, we can calculate the velocity using the formula V=V/t. Therefore, the power of the water is P= FV/t = mgh/t. Substituting the given values, we get P= (1000 kg/m^3)(9.8 m/s^2)(20m)(80m^3)/(60s) = 261,333.33 Watts. This means that the power of the water falling from a height of 20m with a volume of 80m^3 per minute is approximately 261,333.33 Watts. However, this is only the theoretical power of the water. In reality, factors such as air resistance and friction would affect the actual power of the water.