Help With Partial Fraction Decomposition

In summary, the student is trying to solve a homework equation using a partial fractions decomposition, but they get incorrect results.
  • #1
theintarnets
64
0

Homework Statement



I'm supposed to decompose 1 / x(x2 + 1)2
Also, we haven't learned matrices yet so I can't use that technique to solve it.

Homework Equations



None.

The Attempt at a Solution



1 / x(x2 + 1)2 = A/x + (Bx + C) / (x2 + 1) + (Dx + E) / (x2 + 1)2

I multiplied everything by the original denominator to get this:
1 = x3(Bx + C) + x2(A + B + D) + x(C + E) + A

From that, I can tell that A = 1, and I think that the following should also be true, but I'm not 100% certain:
B + D = -1
C + E = 0
B + C = 0

So I set x = -1 which gives me
B - C + 2A + B + D - C - E = 1

And I know that B + D = -1, so I can write:
B - 2C + 2A - 1 - E = 1, and since 2A is just 2, I can rewrite everything as
B - 2C - E = 0
So I take that and add it to my other equation C + E = 0 to cancel out E, and I get
B - C = 0, and then add that to my other equation B + C = 0 and then I get 2B = 0, or just
B = 0, which means D = -1 and C = 0 and E = 0
My final answer would then be
1 / x + x / (x2 + 1) - x / (x2 + 1)2

But that's wrong, because in the answer, only 1 / x is positive. What did I do wrong?
 
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  • #2
theintarnets said:
i multiplied everything by the original denominator to get this:
1 = x3(bx + c) + x2(a + b + d) + x(c + e) + a
This is where your error is.
You should get, by multiplying everything by [itex]x(x^2+1)^2[/itex]
[itex]a(x^2+1)^2 + (bx+c)(x^2+1)x + (dx+e)x = 1[/itex]

From there expand, equate coefficients etc, and you'll get the right answer.
 
  • #3
Ohhhhhhh I see, thank you!
 
  • #4
1 / x(x2 + 1)2 = A/x + (Bx + C) / (x2 + 1) + (Dx + E) / (x2 + 1)2
Anyone know how to get wolframalpha to solve this with least effort? Would be handy to check the answer.
 
  • #5
NascentOxygen said:
Anyone know how to get wolframalpha to solve this with least effort? Would be handy to check the answer.

Just type in the left hand side and it automatically does a partial fractions decomposition for you (4th box):

http://www.wolframalpha.com/input/?i=1/(x(x^2+1)^2)
 
  • #6

Related to Help With Partial Fraction Decomposition

1. What is partial fraction decomposition?

Partial fraction decomposition is a mathematical method used to break down a rational function into simpler fractions. It involves finding the partial fractions that make up the original function by equating the numerators and denominators of the fractions.

2. Why is partial fraction decomposition important?

Partial fraction decomposition is important because it allows us to simplify complex rational functions, making them easier to solve and understand. It also helps in integration and solving differential equations.

3. How do I know when to use partial fraction decomposition?

Partial fraction decomposition is used when you have a rational function with a degree of the numerator being less than the degree of the denominator. It is also used when you need to integrate a rational function using the method of partial fractions.

4. What are the steps involved in partial fraction decomposition?

The steps involved in partial fraction decomposition are as follows:

  1. Factor the denominator of the rational function into linear and irreducible quadratic factors.
  2. Write the partial fraction decomposition as a sum of simpler fractions, one for each factor of the denominator.
  3. Equating the numerators and denominators of the fractions, solve for the unknown coefficients.
  4. Combine the fractions to get the final partial fraction decomposition.

5. Are there any special cases in partial fraction decomposition?

Yes, there are two special cases in partial fraction decomposition: repeated linear factors and repeated irreducible quadratic factors. In these cases, the partial fraction decomposition involves using powers of the repeated factors in the denominators of the fractions.

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