- #1
juanedilio
- 2
- 0
Hi,
I am going through a book on thermal physics (specifically on a section on the 2nd Law)
It talks about an extremely fast adiabatic expression (as a gas in one flask separated by a valve to another flask in vacuum and then the valve is opened).
What I fail to understand is that once the valve is opened and the gas is allowed to reach equilibrium then the final temperature will be the same as the initial temperature (even though Q=0). The ideal gas law tells me that for an adiabatic process when volume increases the temperature must decrease.
Please help me in understanding why the temperature stays the same,
Thanks
I am going through a book on thermal physics (specifically on a section on the 2nd Law)
It talks about an extremely fast adiabatic expression (as a gas in one flask separated by a valve to another flask in vacuum and then the valve is opened).
What I fail to understand is that once the valve is opened and the gas is allowed to reach equilibrium then the final temperature will be the same as the initial temperature (even though Q=0). The ideal gas law tells me that for an adiabatic process when volume increases the temperature must decrease.
Please help me in understanding why the temperature stays the same,
Thanks