- #1
stratz
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Homework Statement
A 75.0g ice cube at 0 C is placed in 825g of water at 25 C. Find final temp.
Homework Equations
Well none really, this should be simple plugging into to heat equations.
The Attempt at a Solution
Heat required to melt ice = (0.075kg)(3.33*10^5) = 24975 J
Heat required to melt ice + Heat required to raise temp of melted ice = heat released from dropping temp of water
24975 + (0.075kg)(4186J/kg C)(Tf) = (0.825)(4186J/kg C)(Tf - 25)
Rearrange the equation: Tf ends up being 35.4, which is impossible. What am I doing wrong?