Gravitational Potential Energy formula

In summary, the formula for gravitational potential in outer space is U = -Gm1m2/r. This is because gravitational potential is defined as the work done in bringing a unit test mass from infinity to a point, and since gravity is an attractive force, negative work is done. Additionally, the gravitational force between two massive objects is inversely proportional to the square of the distance between them, which is why the formula uses r instead of r-squared. Understanding this concept can also help with understanding electric potential energy with point charges.
  • #1
Fizziks_Fan
6
0
Hello all.
I'm studying for sat 2 physics but I still don't understand the formula for gravitational potential in outer space. U = -Gm1m2/r
Can anyone explain this to me? Particularly why G is negative and r is used instead of r-squared.
Newton was such a genius. :bugeye:
 
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  • #2
The gravitational potential is negative by definition. The definition is that
the gravitational potential at a point is the work done in bringing a unit
test mass from infinity to that point. Since the force involved is an attractive force negative work is done in bringing the unit test mass from
infinity to a distance r from the mass being considered.
Also, remember that Work = Force * Distance and that the gravitational
force between 2 massive objects is inversely proportional to the square of the distance between the 2 objects. Without going thru the integration of
F * dr from infinity to a distance r from the massive object you can see
that the work done will be inversely proportional to r when the force is
inversely proportional to r squared. Hope this helps.
 
  • #3
We know the law of gravitation:
[tex]
F = \frac{Gm_1 m_2}{r^2}
[/tex]
We also know that:
[tex]
U = - \int_{x_1}^{x_2} F(x) \,dx
[/tex]
In order to determine gravitational potential energy, we have to think about how much work it takes to get a mass from an infinite distance away to the target distance, [itex]r[/tex]. This is different from previous equations, which have you go from zero distance to the target distance. Once you understand this, you'll get the equation.

Using our two above expressions and the method in the previous paragraph, we can write:
[tex]
U_{grav} = - \int_{\infty}^{r} \frac{Gm_1 m_2}{r^2} \,dr
[/tex]
Which simplifies to (with much cancellation of negative signs):
[tex]
U_{grav} = -\frac{Gm_1 m_2}{r}
[/tex]

The only confusing things are the limits and the idea of going from infinity to the target distance. You'll do a similar thing if you get into electric potential energy with point charges.
 

Related to Gravitational Potential Energy formula

1. What is the formula for gravitational potential energy?

The formula for gravitational potential energy is U = mgh, where U is the gravitational potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.

2. How is gravitational potential energy different from kinetic energy?

Gravitational potential energy is the energy an object possesses due to its position in a gravitational field, while kinetic energy is the energy an object possesses due to its motion. Gravitational potential energy is dependent on the object's height, while kinetic energy is dependent on the object's velocity.

3. What are the units for gravitational potential energy?

The units for gravitational potential energy are joules (J) in the SI system. In the imperial system, the units are foot-pounds (ft-lb).

4. How does the value of gravitational potential energy change with height?

As an object's height increases, its gravitational potential energy also increases. This is because the higher an object is, the more work is required to lift it against the force of gravity, thus increasing its potential energy.

5. Can gravitational potential energy be negative?

Yes, gravitational potential energy can be negative. This occurs when an object is below the reference level, such as when it is below ground level or in a hole. The negative value indicates that work must be done to lift the object to the reference level, thus decreasing its potential energy.

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