Given potential difference of X-ray machine find energy of X rays

In summary, the conversation discusses finding the maximum energy of emitted X-rays in both keV and Joules, using the equation ΔV = U/q where U is the potential energy and q is the charge of an electron. However, the problem arises as the charge of an electron is not given. The solution is to consult a constant's sheet where the charge of an electron can be found and then used to find U.
  • #1
mattdespat
6
0

Homework Statement


Given is the X-ray machine in which electrons are accelerated in the potential difference of 10000 V before hitting the electrode and loosing its energy. Find the maximum energy of the emitted X rays in keV and in Joules.

Homework Equations





The Attempt at a Solution


So for this one I started and though it would be simple using the equation ΔV= U/q, where U would be potential energy and this potential energy would be the maximum energy of the emitted X-rays. Then I realized that I do not have q. I was wondering if I am on the right track and if so am I missing something that would allow me to find q?

Thanks
 
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  • #2
You are given that electrons are accelerated.
What is the charge of an electron ?
 
  • #3
It doesn't say, that is the problem I am having.
 
  • #4
The charge of an electron has been empirically measured and also theoretically predicted/calculated. It should be given in your constant's sheet.
 
  • #5
Ok, so then i can just use that charge to find U right?
Thanks
 

Related to Given potential difference of X-ray machine find energy of X rays

1) How is potential difference related to the energy of X-rays?

Potential difference, also known as voltage, is directly proportional to the energy of X-rays. This means that as the potential difference increases, the energy of the X-rays also increases.

2) Can the energy of X-rays be calculated using the potential difference of an X-ray machine?

Yes, the energy of X-rays can be calculated using the potential difference of an X-ray machine. This can be done using the equation E = qV, where E is the energy, q is the charge of the electron, and V is the potential difference.

3) What is the unit of measurement for potential difference and energy of X-rays?

Potential difference is measured in volts (V), while energy of X-rays is measured in electron volts (eV).

4) Is there a maximum potential difference that an X-ray machine can produce?

Yes, there is a maximum potential difference that an X-ray machine can produce. This is determined by the design and capabilities of the specific machine, and is typically around 150 kilovolts (kV).

5) How does the energy of X-rays affect their ability to penetrate materials?

The energy of X-rays directly affects their ability to penetrate materials. X-rays with higher energy can penetrate thicker and denser materials, while those with lower energy may only be able to penetrate thinner and less dense materials.

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