Generalization of a theorem in Real Analysis

In summary: I am not an expert in that area, so I cannot say for certain.Homework Statement If ##\{K_\alpha\}## is a collection of compact subsets of a metric space X, such that the intersection of every finite subcollection of {##K_\alpha##} is nonempty, then ##\cap K_\alpha## is nonempty. Generalize this theorem and proof the generalization. Why doesn't it make sense to state the theorem in its general form?
  • #1
Silviu
624
11

Homework Statement


If ##\{K_\alpha\}## is a collection of compact subsets of a metric space X, such that the intersection of every finite subcollection of {##K_\alpha##} is nonempty, then ##\cap K_\alpha## is nonempty. Generalize this theorem and proof the generalization. Why doesn't it make sense to state the theorem in its general form?

Homework Equations

The Attempt at a Solution


I know how to prove the actual theorem, but I don't really know what is its generalization in order to attempt to prove it. I don't want yet a proof of the generalization, just its statement. Thank you.
 
Physics news on Phys.org
  • #2
Silviu said:

Homework Statement


If ##\{K_\alpha\}## is a collection of compact subsets of a metric space X, such that the intersection of every finite subcollection of {##K_\alpha##} is nonempty, then ##\cap K_\alpha## is nonempty. Generalize this theorem and proof the generalization. Why doesn't it make sense to state the theorem in its general form?

Homework Equations

The Attempt at a Solution


I know how to prove the actual theorem, but I don't really know what is its generalization in order to attempt to prove it. I don't want yet a proof of the generalization, just its statement. Thank you.
Seems to me that the generalization would change "finite subcolledtion" to "infinite subcollection."
 
  • #3
Mark44 said:
Seems to me that the generalization would change "finite subcolledtion" to "infinite subcollection."
Thank you for your reply. However, doesn't that make the statement redundant? If any infinite intersection is non-empty, the intersection of all K is by assumption non-empty, so there is nothing left to prove (and it seems actually weaker than the other one).
 
  • #4
Silviu said:

Homework Statement


If ##\{K_\alpha\}## is a collection of compact subsets of a metric space X, such that the intersection of every finite subcollection of {##K_\alpha##} is nonempty, then ##\cap K_\alpha## is nonempty. Generalize this theorem and proof the generalization. Why doesn't it make sense to state the theorem in its general form?

Homework Equations

The Attempt at a Solution


I know how to prove the actual theorem, but I don't really know what is its generalization in order to attempt to prove it. I don't want yet a proof of the generalization, just its statement. Thank you.

There are generalizations of metric spaces. See, eg., https://en.wikipedia.org/wiki/Normal_space . In some of those spaces you might be able to generalize the concept of "compactness"; see, eg., https://en.wikipedia.org/wiki/Compact_space

Perhaps a version of your cited theorem remains true for some of those generalizations.
 

Related to Generalization of a theorem in Real Analysis

1. What is the definition of generalization in Real Analysis?

Generalization in Real Analysis is the process of extending a specific theorem or concept to a more broad or general setting. This involves applying the same principles and techniques used in the original theorem to a larger class of objects or situations.

2. Why is generalization important in Real Analysis?

Generalization allows for a deeper understanding of mathematical concepts and allows for the application of theorems to a wider range of problems. It also helps to establish connections between seemingly unrelated ideas and can lead to the discovery of new theorems.

3. How is a theorem generalized in Real Analysis?

A theorem is generalized in Real Analysis by identifying the key elements and assumptions of the original theorem and then modifying them to apply to a broader class of objects or situations. This may involve loosening restrictions or assumptions, or introducing new variables or concepts.

4. What challenges may arise when generalizing a theorem in Real Analysis?

One challenge that may arise when generalizing a theorem in Real Analysis is ensuring that the generalized theorem is still true and applicable in all cases. This may require additional proof techniques or a deeper understanding of the underlying concepts. Another challenge may be determining the scope of the generalization and whether it is applicable to all situations or only a certain subset.

5. Can any theorem in Real Analysis be generalized?

Not all theorems in Real Analysis can be successfully generalized. Some theorems may have very specific conditions or assumptions that cannot be modified without fundamentally changing the result. Additionally, the process of generalization may lead to more complicated or specialized theorems that may not have the same level of practical application as the original theorem.

Similar threads

  • Calculus and Beyond Homework Help
Replies
4
Views
923
  • Calculus and Beyond Homework Help
Replies
3
Views
605
  • Calculus and Beyond Homework Help
Replies
1
Views
562
Replies
1
Views
2K
  • Calculus and Beyond Homework Help
Replies
3
Views
2K
  • Calculus and Beyond Homework Help
Replies
22
Views
1K
  • Calculus and Beyond Homework Help
Replies
14
Views
1K
  • Calculus and Beyond Homework Help
Replies
1
Views
1K
Replies
2
Views
1K
  • Calculus and Beyond Homework Help
Replies
3
Views
4K
Back
Top