Function notation and shifting functions

In summary, the conversation discusses how to model the velocity of a particle using two different stopwatches. It is important to note the difference between the arguments used in the functions ##\vec{v}(T)## and ##\vec{v}(t)##, and to consider potential ambiguity when using these functions. To avoid confusion, a new function, ##\vec{u}(t)##, can be created to represent velocity in terms of the reading on the second stopwatch.
  • #1
PFuser1232
479
20
Suppose two people, X and Y, have two different stopwatches. X starts his/her stopwatch as some particle passes an origin. We can model the velocity of the particle by ##\vec{v}(T)##, where ##T## is the reading on the first stopwatch. After an amount of time ##\Delta t##, Y starts his/her stopwatch (##T = t + \Delta t##). Is it correct to model the velocity of the particle as ##\vec{v}(t)## where ##t## is the reading on the second stopwatch? Or should we change the letter used to represent the function [to ##\vec{u}(t)## for example]?
 
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  • #2
It depends. If you are always using ##\vec{v}(T)## and ##\vec{v}(t)##, then there is no ambiguity. But if somewhere you are to write something like ##\vec{v}(0)##, then it is not clear which time you are referring to.
 
  • #3
DrClaude said:
It depends. If you are always using ##\vec{v}(T)## and ##\vec{v}(t)##, then there is no ambiguity. But if somewhere you are to write something like ##\vec{v}(0)##, then it is not clear which time you are referring to.

I think it's because the argument of the function ##\vec{v}## as defined earlier always represents the reading on the first stopwatch. To represent velocity in terms of the reading on the second stopwatch a new function is forced upon us such that ##\vec{u}(t) = \vec{v}(T)## for all ##t##. Is this correct?
 
  • #4
MohammedRady97 said:
I think it's because the argument of the function ##\vec{v}## as defined earlier always represents the reading on the first stopwatch. To represent velocity in terms of the reading on the second stopwatch a new function is forced upon us such that ##\vec{u}(t) = \vec{v}(T)## for all ##t##. Is this correct?
That equation looks correct. Since ##T = t + \Delta t##, you recover the correct behavior, e.g.,
$$
\vec{u}(0) = \vec{v}(\Delta t)
$$
 
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Related to Function notation and shifting functions

1. What is function notation?

Function notation is a way of representing a function using symbols and variables. It is commonly written as f(x), where f is the name of the function and x is the input value. It helps us understand the relationship between the input and output values of a function.

2. How do you evaluate a function using function notation?

To evaluate a function using function notation, we substitute the input value given in the parentheses for the variable in the function. For example, if we have f(x) = 2x + 3 and we want to evaluate f(4), we would replace x with 4 and solve the equation to get f(4) = 11.

3. What is the difference between vertical and horizontal shifting of a function?

Vertical shifting of a function refers to moving the entire graph of the function up or down on the y-axis, while keeping the shape of the graph the same. Horizontal shifting, on the other hand, involves moving the graph left or right on the x-axis. This can be done by adding or subtracting a constant value to the original function.

4. How do you determine the direction and amount of shifting in a function?

The direction and amount of shifting in a function can be determined by looking at the sign and value of the constant being added or subtracted. For vertical shifting, positive values will shift the graph up, while negative values will shift it down. For horizontal shifting, positive values will shift the graph to the left, while negative values will shift it to the right.

5. Can a function be shifted in both the vertical and horizontal direction?

Yes, a function can be shifted in both the vertical and horizontal direction at the same time. This can be done by adding or subtracting a constant value to both the x and y values of the original function. The order in which the shifting is done does not matter, as long as the constant values are correctly added or subtracted.

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