Formation Reaction Problems: No Idea how to solve it

[leftync1128]

Write formation reactions at 1 atmosphere pressure and 25°C for each of the following substnaces:
Mercury (I) chloride solid
Nitroethane (CH3CH2NO2) liquid

I have absolutely no idea how to do this. If anyone can help show or explain to me how to solve this, I'd appreciate it

 

[BlackHole213]

Are you sure it is 25 degrees C because the 1 atmosphere (101.325 kpa) is STP but the 25 degrees C is not at STP, but SATP.

If you know how to write normal formation reactions, write it that way. However, do not take my word for law. I'd suggest to ask you teacher if no one else on this forum answers this question.

 

[quicknote]

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I understand that formation reactions involve the formation of a compound from its constituent elements. The key to solving these types of problems is to first identify the elements present in the compound and then determine the balanced chemical equation for their formation.

For Mercury (I) chloride solid, the compound is composed of mercury (Hg) and chlorine (Cl). The balanced chemical equation for its formation at standard conditions (1 atm pressure and 25°C) would be:

Hg (s) + Cl2 (g) → HgCl (s)

This reaction shows that one molecule of mercury reacts with one molecule of chlorine gas to form one molecule of mercury (I) chloride solid.

For Nitroethane (CH3CH2NO2) liquid, the compound is composed of carbon (C), hydrogen (H), nitrogen (N), and oxygen (O). The balanced chemical equation for its formation at standard conditions would be:

2 C2H6 (g) + 2 HNO3 (g) → 2 CH3CH2NO2 (l) + 4 H2O (l)

This reaction shows that two molecules of ethane (C2H6) react with two molecules of nitric acid (HNO3) to form two molecules of nitroethane (CH3CH2NO2) liquid and four molecules of water (H2O).

It is important to note that these reactions are balanced in terms of both atoms and charges. This means that the number of each type of atom on both sides of the equation is the same, and the overall charge is also balanced. I hope this helps you understand how to approach formation reaction problems. If you have any further questions, please do not hesitate to reach out to me for clarification.