Forces on a rolling body with sliding bodies on it.

In summary, the conversation discusses a problem involving forces and a pulley. The equations used to solve the problem are F=ma, K=m2a2, and N=m1a. The concept of tension in a physical, massless rope is also discussed, with the conclusion that the pulley must provide a force to keep the rope in place. The force from the pulley is always at a 45 degree angle with a magnitude of the square root of two times the tension. The conversation ends with the individual expressing gratitude for the new knowledge gained.
  • #1
Icelove
16
0

Homework Statement



I'm attaching a picture for the problem.

Homework Equations



F - N - K(that's my problem) = Ma

K = m2a2

N = m1a (the acceleration is the same, since the rolling body pushes the m1 body forward)

m1g - K = m1a1 (this is the acceleration in the y direction)

a2 = a + a1 (this is obvious)

The Attempt at a Solution



Well I know how to solve it now(since I know the force diagram). I just don't know
how that K tension force started to act on the rolling body.

BTW! If you know similar force problems I would really, really love you for it.
Imho this is pretty complex, I was wondering about non-calculus based, very complex
force problems, examples so I can prepare.

Thanks!
 

Attachments

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  • #2
Ok, I haven't checked your solution, since your main question concerned how "K" radiated, as you call it, through the pulley.

Remember that the rope is a physical object, and that it is idealized in having zero mass. Agreed?

But, obviously, the rope being physical can be subject to forces, i.e, it must obey Newton's 2.law of motion!

And, since the rope cannot have infinite acceleration, the 2.law of motion for a physical, massless object must be: F=0, where F is the sum of external forces acting upon it.

But, note that the force on the rope from box 1 is horizontally acting , whereas the force on the rope from box 2 is vertically acting.

If you add those forces vectorially (taking the directions into the account, not just the magnitude we call rope tension), you do NOT get 0 as your vectorial sum.

In order to get that, the PULLEY must provide a force on the rope, to keep in place actually (remove the pulley, and the rope would flop down on the trolley pretty quickly, indicating a force acting upon it from the removed pulley).

And THEN, it is simple to understand how the rope "radiates" some force onto the trolley:

It is simply the result of Newtons 3.law, about action and reaction.
 
  • #3
Why haven't I thought of that?! Thank you very much.

Just to be clear that I understand it perfectly. If the trolley would be a stationary object,
Newton's 3rd law would still hold and those red K forces would still apply, we just wouldn't need
them to calculate anything so it's pointless to draw them. Otherwise the rope would accelerate in a 45degrees(in this picture anyways) path to infinity.
I hope I'm right. :)

Thanks again for the help, because this is a huge new knowledge application for me.

ps.: If the pulley was in let's say 60 degrees from the horizontal, would the red K forces still be the same? I understand the the pulley must provide force on the rope but now it's in a different angle, so the total sqrt(2)*K total force would still "radiate" through the pulley, but the x-y components wouldn't be the same. That is my thought process, please correct me if I'm mistaken.
 
Last edited:
  • #4
Icelove said:
Why haven't I thought of that?! Thank you very much.

Just to be clear that I understand it perfectly. If the trolley would be a stationary object,
Newton's 3rd law would still hold and those red K forces would still apply, we just wouldn't need
them to calculate anything so it's pointless to draw them. Otherwise the rope would accelerate in a 45degrees(in this picture anyways) path to infinity.
I hope I'm right. :)
Correct.
Or, alternatively, you'd have to include in your relevant free body diagram the forces action on the trolley from the ground, in order to keep it stationary.

(It is fairly conventional, though, that we do not include "statics" forces in the FBD, and only take into consideration those forces relevant to the motion we want to describe.)

Thanks again for the help, because this is a huge new knowledge application for me.
You're welcome!
ps.: If the pulley was in let's say 60 degrees from the horizontal, would the red K forces still be the same? I understand the the pulley must provide force on the rope but now it's in a different angle, so the total sqrt(2)*K total force would still "radiate" through the pulley, but the x-y components wouldn't be the same. That is my thought process, please correct me if I'm mistaken.
The pulley must still provide the necessary force to keep the rope "wrapped" around it.
Modelling the rope as massless, and with no friction being present necessitates constant tension throughout the rope.
Thus, if one end of the rope is modeled as strictly horizontal, the other modeled as strictly vertical, then the force from the pulley must be a 45 degree force with "square root of two" times tension in magnitude, irrespective of the pulley's own angle.
 
  • #5


I would like to clarify a few things about this problem before providing a response. Firstly, can you provide more context for the problem? What is the scenario or situation being described? Secondly, can you explain what the variables and equations represent? It would be helpful to have a clear understanding of the problem before attempting to solve it.

In general, when considering forces on a rolling body with sliding bodies on it, we need to take into account the forces acting on each individual body as well as the interactions between them. These forces can include gravity, friction, and normal forces.

Without further information, it is difficult to provide a specific response to this problem. However, I can suggest some general strategies for solving complex force problems. Firstly, draw a clear and accurate force diagram for each body involved in the problem. This will help you visualize the forces and their directions. Next, identify all the forces acting on each body and use Newton's laws of motion to determine the net force and resulting acceleration. It may also be helpful to consider the conservation of energy and momentum in some cases.

As for non-calculus based, complex force problems, I would suggest looking into problems involving pulleys, inclined planes, and systems of connected bodies. These types of problems often require a combination of mathematical analysis and conceptual understanding of forces and their interactions.

In conclusion, as a scientist, I would approach this problem by first clarifying the scenario and variables involved, then drawing a force diagram and applying Newton's laws of motion to determine the net forces and resulting acceleration. I would also suggest exploring similar force problems to gain a better understanding of complex force systems.
 

Related to Forces on a rolling body with sliding bodies on it.

1. What is the difference between static and kinetic friction?

Static friction is the force that resists motion between two surfaces that are not moving relative to each other. Kinetic friction is the force that resists motion when two surfaces are sliding against each other.

2. How does the weight of an object affect the forces on a rolling body with sliding bodies on it?

The weight of an object affects the forces on a rolling body with sliding bodies by increasing the amount of friction between the surfaces. This can make it more difficult for the object to roll smoothly and may cause it to slow down or stop completely.

3. What other factors can affect the forces on a rolling body with sliding bodies on it?

Other factors that can affect the forces on a rolling body with sliding bodies include the surface materials, the speed and direction of the rolling body, and the presence of any external forces, such as winds or gravity.

4. How do forces on a rolling body with sliding bodies on it affect its acceleration?

The forces on a rolling body with sliding bodies can affect its acceleration by either increasing or decreasing its speed. If the force of friction is greater than the force of motion, the object will decelerate. If the force of motion is greater than the force of friction, the object will accelerate.

5. Can the forces on a rolling body with sliding bodies on it be calculated?

Yes, the forces on a rolling body with sliding bodies can be calculated using equations such as Newton's second law of motion (F=ma) and the coefficient of friction. However, the exact forces may vary depending on the specific conditions and variables involved.

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