Since's there's no component of acceleration in the direction of cos(θ), the component of force from gravity and the opposing normal force from the plane in the direction cos(θ) will be m g cos(θ) (as Doc Al just posted), in either the sliding or the rolling case.sodaboy7 said:I am asking about forces perpendicular to surface not along the surface. So will there be any force other than m g cos(θ)?
The force exerted by a rolling body is the force that is produced by the movement of an object as it rolls along a surface. This force is also known as rolling resistance and it is caused by the interaction between the rolling object and the surface it is rolling on.
The force exerted by a rolling body can be calculated using the formula F = μmg, where F is the force, μ is the coefficient of rolling friction, m is the mass of the object, and g is the acceleration due to gravity. This formula takes into account the weight of the object and the friction between the object and the surface.
There are several factors that can affect the force exerted by a rolling body, including the mass and shape of the object, the coefficient of rolling friction, the speed at which the object is rolling, and the type of surface the object is rolling on. These factors can all impact the amount of force required to keep the object rolling.
The force exerted by a rolling body can either help or hinder its motion. If the force is greater than the resistance caused by friction, the object will continue to roll at a constant speed. However, if the force is less than the resistance, the object will slow down and eventually come to a stop.
The force exerted by a rolling body can be reduced by minimizing the friction between the rolling object and the surface it is rolling on. This can be achieved by using smoother surfaces, reducing the weight of the object, or using materials with lower coefficients of friction. Additionally, reducing the speed at which the object is rolling can also decrease the force exerted.