First order differential equation

In summary: Hi Romaha_1! Welcome to PF! :smile:(try using the X2 tag just above the Reply box :wink:)Having said that, I don't see how z = x2*e2y does it … perhaps I'm misreading the question? :redface:
  • #1
Romaha_1
5
0

Homework Statement



Solve the differential equation:

Homework Equations



1+(x-x^2*e^(2y))(dy/dx) = 0

The Attempt at a Solution



No idea how to approach this.
 
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  • #2
Romaha_1 said:

Homework Statement



Solve the differential equation:

Homework Equations



1+(x-x^2*e^(2y))(dy/dx) = 0

The Attempt at a Solution



No idea how to approach this.
It looks pretty clear to me. Basic algebra gives
[tex]x(1- e^{2y})dy/dx= -1[/tex]
and then separate variables as
[tex](1- e^{2y})dy= -\frac{1}{x}dx[/tex]

Now integrate.
 
  • #3
HallsofIvy said:
It looks pretty clear to me. Basic algebra gives
[tex]x(1- e^{2y})dy/dx= -1[/tex]
and then separate variables as
[tex](1- e^{2y})dy= -\frac{1}{x}dx[/tex]

Now integrate.

Hmm, there's an x^2 in the equation, I think you missed that bit.
 
  • #4
Hi Romaha_1! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

Does putting z = e2y help? :smile:
 
  • #5
tiny-tim said:
Hi Romaha_1! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

Does putting z = e2y help? :smile:

No it doesn't, does it?
 
  • #6
JFonseka said:
Hmm, there's an x^2 in the equation, I think you missed that bit.

Yes, that's the reason I don't know how to do it. I don't think it is a mistake in the problem, since there is a sign "(very tricky)" after it on the problem set.
 
  • #7
Altabeh said:
No it doesn't, does it?

Doesn't it? :smile:
 
  • #8
Romaha_1 said:
Yes, that's the reason I don't know how to do it. I don't think it is a mistake in the problem, since there is a sign "(very tricky)" after it on the problem set.

The question isn't necessarily wrong, I'm not too good at this stuff at all. It just seemed to me that HallsofIvy was attempting the separable ODE approach, but missed the x^2.

I think it should be:

(e^2y)*dy = ((-1-x)/(-x^2))*dx

(e[tex]^{2y}[/tex])*dy = ([tex]\frac{1-x}{-x^{2}}[/tex])*dx

after the separation.

Now you must integrate it. I'm not too sure if I'm right, so be careful.
 
Last edited:
  • #9
JFonseka said:
The question isn't necessarily wrong, I'm not too good at this stuff at all. It just seemed to me that HallsofIvy was attempting the separable ODE approach, but missed the x^2.

Yeah, I understand what you meant and agree with you that the separable approach does not work; it was my assumption that the question was wrong.
 
  • #10
Romaha_1 said:
Yeah, I understand what you meant and agree with you that the separable approach does not work; it was my assumption that the question was wrong.

I never said the Separable ODE approach doesn't work.
 
  • #11
JFonseka said:
I never said the Separable ODE approach doesn't work.

Sorry, for some reason I could not see the end of your previous post. But still, I do not understnad how this works because the whole expression (x-x2*e2y) is multiplied by dy/dx, not just x2*e2y.
 
  • #12
tiny-tim said:
Hi Romaha_1! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

Does putting z = e2y help? :smile:

Hi tiny-tim, thank you for the idea!

But I could solve it only when letting z = x2*e2y; I still do not see how this is possible with z = e2y.
 
  • #13
Romaha_1 said:
No idea how to approach this.
tiny-tim said:
Does putting z = e2y help? :smile:
Romaha_1 said:
Hi tiny-tim, thank you for the idea!

But I could solve it only when letting z = x2*e2y; I still do not see how this is possible with z = e2y.

ah … on this forum, we don't give you the full answer …

so, since you had no idea, I sort-of pushed you half-way (-1 = (x - x2z)(1/2z)dz/dx), and left you to finish it. :wink:

having said that, I don't see how z = x2*e2y does it … perhaps I'm misreading the question? :redface:
 

Related to First order differential equation

1. What is a first order differential equation?

A first order differential equation is a mathematical equation that relates a function to its derivative, or rate of change. It is called "first order" because it involves only the first derivative of the function.

2. What is the general form of a first order differential equation?

The general form of a first order differential equation is dy/dx = f(x,y), where y is the dependent variable, x is the independent variable, and f(x,y) is a function that relates the two variables.

3. How is a first order differential equation solved?

There are several methods for solving first order differential equations, including separation of variables, integrating factors, and using a substitution. The specific method used depends on the form of the equation and the initial conditions given.

4. What is the significance of a first order differential equation in science?

First order differential equations are used to model various physical, biological, and social phenomena in science. They provide a mathematical framework for understanding and predicting how systems change over time.

5. Can a first order differential equation have multiple solutions?

Yes, a first order differential equation can have multiple solutions. This is because the equation represents a family of functions rather than a single function, and different initial conditions can yield different solutions.

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