- #1
Lori
1. Homework Statement
Given x and y position ... find magnitude of both velocity and acceleration and their direction at t = 2 ?
x = 4t
y = 30 - 2.2t^2
would the velocity's magnitude be sqrt(8^2 + 8.8^2) ?
Homework Equations
v = sqrt(vy^2 + vx^2)
The Attempt at a Solution
vy = -8.8
vx= 8
v = sqrt((8)^2 +(-8.8^2)) = 11.89 m/s
atan(8/) = 42 degrees east of south
Is this how I'm suppose to find velocity?
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