Finding Thevenin Voltage in a Complex Circuit

In summary, the question is about determining the Thevenin voltage in a circuit with resistors in series and parallel. The 10 and 20 ohm resistors are in series, as well as the 50 and 40 ohm resistors, resulting in a total resistance of 30 ohms and 90 ohms respectively. These two branches are then in parallel, with a combined resistance of 22.5 ohms. The discussion also mentions ignoring the terminals A and B, which are open and do not pass any current. It is explained that the current will divide equally between the branches due to their equal resistances in parallel. Terminal A and B are then referred back to as the only available paths for the current to
  • #1
sugz
110
0

Homework Statement


The question is in the photo attached.

Homework Equations

The Attempt at a Solution


I have found the Thevenin voltage as the 10 and 20 ohm resistors are in series (30 ohms) and the 50 and 40 ohm resistor are in series (90ohms). The 30 and 90 ohm resistors are in parallel so

30||90 = (30×90)/(30+90) =22.5 ohms

I am having struggles with determine the Thevenin voltage as the solution says the 8 A current gets divided equally among the 10 and 20 ohm resistor but I don't understand why.
 

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  • #2
What is the total resistance of each branch (ignore the terminals A and B for the moment)?
 
  • #3
60 ohms but how can we ignore terminals a and b?
 
  • #4
sugz said:
60 ohms but how can we ignore terminals a and b?
I said ignore them for the moment. You can do this because they are open: not connected to anything so they do not pass any current.

So both of these branches have the same resistance, correct? The branches are in parallel, correct? How will current divide between equal resistances in parallel?
 
  • #5
So since current doesn't pass through terminal a and b, they just flow down to the next resistor?
 
  • #6
sugz said:
So since current doesn't pass through terminal a and b, they just flow down to the next resistor?
Yes. They are the only available paths.
 
  • #7
Okay, that makes sense then, thank you!
 

Related to Finding Thevenin Voltage in a Complex Circuit

What is a Thevenin Equivalent Circuit?

A Thevenin Equivalent Circuit is a simplified representation of a complex electrical circuit that consists of a voltage source and a single resistor. It is used to model the behavior of a complex circuit, making it easier to analyze and understand.

How is a Thevenin Equivalent Circuit calculated?

To calculate a Thevenin Equivalent Circuit, the original circuit is disconnected from all loads and the voltage at the load terminals is measured. This voltage is the Thevenin voltage. The original circuit is then replaced with a voltage source equal to the Thevenin voltage and a single resistor equal to the equivalent resistance of the original circuit when viewed from the load terminals.

What are the advantages of using a Thevenin Equivalent Circuit?

Using a Thevenin Equivalent Circuit makes complex circuit analysis easier and more efficient. It allows for the prediction of circuit behavior without having to solve for all the individual circuit components. It also helps in troubleshooting by isolating the effects of a particular component on the overall circuit.

What are the limitations of a Thevenin Equivalent Circuit?

A Thevenin Equivalent Circuit is only an approximation of the original circuit and is not always accurate. It assumes that the behavior of the circuit is linear and does not take into account non-linear components. It also does not account for the effects of external factors such as temperature and frequency.

How is a Thevenin Equivalent Circuit used in practical applications?

Thevenin Equivalent Circuits are commonly used in the design and analysis of electronic systems. They help in simplifying the circuit and determining the optimal values for components. They are also useful in circuit simulation software, allowing for quick and accurate analysis of complex circuits.

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