drop said:Basically I don't know anyone in real life that can help me with this, so I need help checking to see if my answers are correct :)
PART A
11) Find the vertex of f(x) = -2x^2 - 8x + 3 algebraically.
My Answer: (-2,0)
drop said:12) Multiply and simplify: (6 - 5i) (4 + 3i)
My Answer: 39 - 2i
The vertex of a quadratic equation is the point on the graph where the parabola changes direction. It is also the maximum or minimum point of the parabola, depending on whether the parabola opens upward or downward.
To find the vertex of a quadratic equation, you can use the formula x = -b/2a, where a and b are the coefficients of the quadratic equation in the form ax^2 + bx + c. This will give you the x-coordinate of the vertex. To find the y-coordinate, substitute the x-coordinate into the original equation.
The product of two complex numbers is another complex number. It is found by multiplying the real parts and the imaginary parts of the two numbers separately and then combining them.
To find the product of two complex numbers, you can use the FOIL method, which stands for First, Outer, Inner, Last. Multiply the first terms, then the outer terms, then the inner terms, and finally the last terms. This will give you the real and imaginary parts of the product, which can then be combined.
Yes, the vertex of a quadratic equation can be a complex number. This happens when the quadratic equation has complex roots, meaning the solutions involve the imaginary unit i. In this case, the vertex will have a real and imaginary part.