I don't think so. It's probably easier to work with the mm units that were given.Abel I Daniel said:Homework Statement
8 Charged drops of water each of radius 1 mm and having a charge of 10^(-10) Coloumbs are combined to form a bigger drop.Determine the potential of the bigger drop.
Homework Equations
Does the radius becomes 4*10^(-3)m,when it combines?
Abel I Daniel said:Does the charge sum up to 9*10^(-10)?The Attempt at a Solution
[/B]
Used the formula -V=9*10^(9)*Q/r
Got the ans as 1800 V.
Mark44 said:I don't think so. It's probably easier to work with the mm units that were given.
What's the volume of one rain drop?
If you combine 8 rain drops into one bigger drop, what is the volume of this larger drop? What's its radius?
Or more simply, 4/3 ##\pi##, the volume of one rain drop,Abel I Daniel said:I assume the volume to be (4/3)*(pi)*r^3,where r is 1 mm.
From the formula you wrote in post #1, the potential V is a function of the radius r.Abel I Daniel said:But what potential has to do with Volume.i am quit weak in this subject
If 8 rain drops combine into one larger drop, what's the volume of the larger rain drop? What's the radius of the larger rain drop?-V=9*10^(9)*Q/r
i hope it adds up linearliy,that means ,radius of larger frop =8* 1mm (radius of each smaller drop)Mark44 said:If 8 rain drops combine into one larger drop, what's the volume of the larger rain drop? What's the radius of the larger rain drop?
No, it doesn't.Abel I Daniel said:i hope it adds up linearliy,that means ,radius of larger frop =8* 1mm (radius of each smaller drop)
the bigger radius becomes twice the smaller radius ie 2 mm.But what about the charge ?Mark44 said:The volumes add like you think they would, but the radius of the combined raindrop is NOT 8mm.
Electric potential is a measure of the electric potential energy per unit charge at a certain point in space. It is a scalar quantity and is measured in volts (V).
Electric potential is a measure of the potential energy of a charge at a certain point, while electric field is a measure of the force that a charge would experience at that point. Electric potential is a scalar quantity, while electric field is a vector quantity.
The formula for electric potential is V = kQ/r, where V is the electric potential, k is the Coulomb's constant (9x10^9 Nm^2/C^2), Q is the charge, and r is the distance between the charge and the point at which the electric potential is being calculated.
Electric potential can be measured using a voltmeter, which measures the potential difference between two points in an electric field. The unit of measurement for electric potential is volts (V).
The electric potential at a point is affected by the amount of charge present, the distance from the charge, and the medium in which the charge is located. It is also affected by the presence of other charges in the surrounding area, as well as any external electric fields.